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borishaifa [10]
3 years ago
15

Find the projection of u onto v URGENT HELP

Mathematics
1 answer:
padilas [110]3 years ago
3 0

Given:

Two vectors are:

u=\left

v=\left

To find:

The projection of u onto v.

Solution:

Magnitude of a vector v=\left is:

|v|=\sqrt{a^2+b^2}

Dot product of two vector v_1=\left and v_2=\left is:

v_1\cdot v_2=a_1a_2+b_1b_2

Formula for projection of u onto v is:

Proj_vu=\dfrac{u\cdot v}{|v|^2}v

Proj_vu=\dfrac{\left \cdot \left }{(\sqrt{2^2+17^2)^2}}\left

Proj_vu=\dfrac{0\cdot 2+6\cdot 17}{4+289}\left

Proj_vu=\dfrac{0+102}{293}\left

On further simplification, we get

Proj_vu=\dfrac{102}{293}\left

Proj_vu=\left

Proj_vu=\left

Therefore, the projection of u onto v is Proj_vu=\left.

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ollegr [7]

Answer:

x = 26.45

Step-by-step explanation:

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cos 50 = 17 /x

Switch the x and the cos 50

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Rounding to 2 decimal places

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8 0
3 years ago
You are in a hot air balloon looking down at two ponds. Pond A which is in front of your balloon, is at an angle of depression t
MatroZZZ [7]

a. See attachment for the labelled diagram

b. Using the sine ratio, distance from the hot air to pond A is 5,038.9 m, while distance from the hot air to pond B is 6,287.1 m.

c. Distance between the two ponds is 1,263.5 m.

<h3>What is the Sine and Tangent Ratios?</h3>

Sine ratio, is: sin ∅ = opposite side/hypotenuse length

Tangent ratio is: tan ∅ = opposite side/adjacent length.

a. The diagram with the appropriate labels is shown in the image attached below.

b. Use the sine ratio to find the distance from the hot air to pond A (CA) and to pond B (CB):

CA = hypotenuse

∅ = 10°

Opposite = 875 m

sin 10 = 875/CA

CA = 875/sin 10

CA ≈ 5,038.9 m (distance from the hot air to pond A)

CB = hypotenuse

∅ = 8°

Opposite = 875 m

sin 8 = 875/CB

CB = 875/sin 8

CB ≈ 6,287.1 m (distance from the hot air to pond B)

c. Distance between the two ponds, BA = BD + DA.

Apply the tangent ratio to find BD and DA

tan 8 = 875/BD

BD = 875/tan 8

BD = 6,225.9 m

tan 10 = 875/DA

DA = 875/tan 10

DA = 4,962.4 m

Distance between the two ponds = 6,225.9 - 4,962.4 = 1,263.5 m.

Learn more about the sine and tangent ratios on:

brainly.com/question/24137232

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8 0
2 years ago
What is the density of an object having a mass of 25 g and a volume of 8.0 cm cubed
weqwewe [10]

Answer:

3.125 g/cm³.

Step-by-step explanation:

The formula for density/mass/volume is d = m/v, where d is density in grams per cm cubed, m is in grams, and v is in cm cubed.

In this case, m = 25 and v = 8.0.

d = 25 / 8.0

d = 25 / 8

d = 3.125.

So, the density of the object is 3.125 g/cm cubed.

Hope this helps!

6 0
3 years ago
PLEASE HELP ME :)))Micheal is making scale drawings of rectangular rooms using a scale of 1in to 1 1/2 feet
Aleksandr-060686 [28]

Answer:

a) 256 ft^2 No

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c) 300 ft^2 NO

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w=8.5 in

l=11 in

A=w•l

A=8.5•11=93.5 in^2

Scale:

1in:1.5 ft

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1in ^2. 2.25ft^2

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X=210.375

Step-by-step explanation:

3 0
3 years ago
-5x+9=24 <br> WILL GIVE BRAINLIEST
natali 33 [55]

Answer:

x = -3

Step-by-step explanation:

24-9= 15

15/-5=-3

5 0
3 years ago
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