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3 years ago

What is the domain of the function RX) = x2 + 3x + 5?

Mathematics

2 answers:

Free_Kalibri [48]3 years ago

8 0

Answer:

all real numbers

Step-by-step explanation:

The domain is the numbers that the input, x, can take

We can put in any real number for x since there are no restrictions on the input

Natalija [7]3 years ago

8 0

Answer:

option D is domain

Step-by-step explanation:

because no change is happen in range by keeping any real number

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What is the equation of the line?

ki77a [65]

Answer:

y=1/2+2

Step-by-step explanation:

go up 1 and right 2 thats how you get 1/2 also its 2 point above the orgin so its +2

remember y=x+b 1/2 is the x(slope) and 2 is b

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2 years ago

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Patel uses long division to find the decinal equivalent to 37/16 which statement(s) could be true regarding the decimal equivale

galben [10]

The answer it is 2.5

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4 years ago

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Pls help me asap !!!!!

vichka [17]

Step-by-step explanation:

the option with the isoceles triangles can NOT be just of that proof, because nowhere is it defined or proven that there is or are isoceles triangles involved. even though the picture looks like it, but that does not mean anything for the formal proof.

actually, this proof is the same (and is also valid) for non-isoceles triangles.

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3 years ago

Help please ITS OF TRIGONOMETRY<br>PROVE

Flauer [41]

Answer:

The equation is true.

Step-by-step explanation:

In order to solve this problem, one must envision a right triangle. A diagram used to represent the imagined right triangle is included at the bottom of this explanation. Please note that each side is named with respect to the angle is it across from.

Right angle trigonometry is composed of a sequence of ratios that relate the sides and angles of a right triangle. These ratios are as follows,

$sin(\theta)=\frac{opposite}{hypotenuse}\\\\cos(\theta)=\frac{adjacent}{hypotenuse}\\\\tan(\theta)=\frac{opposite}{adjacent}$

One is given the following equation,

$\frac{sin(A)+sin(B)}{cos(A) +cos(B)}+\frac{cos(A)-cos(B)}{sin(A)-sin(B)}=0$

As per the attached reference image, one can state the following, using the right angle trigonometric ratios,

$sin(A)=\frac{a}{c}\\\\sin(B)=\frac{b}{c}\\\\cos(A)=\frac{b}{c}\\\\cos(B)=\frac{a}{c}$

Substitute these values into the given equation. Then simplify the equation to prove the idenity,

$\frac{sin(A)+sin(B)}{cos(A) +cos(B)}+\frac{cos(A)-cos(B)}{sin(A)-sin(B)}=0$

$\frac{\frac{a}{c}+\frac{b}{c}}{\frac{b}{c}+\frac{a}{c}}+\frac{\frac{b}{c}-\frac{a}{c}}{\frac{a}{c}-\frac{b}{c}}=0$

$\frac{\frac{a+b}{c}}{\frac{a+b}{c}}+\frac{\frac{b-a}{c}}{\frac{a-b}{c}}$

Remember, any number over itself equals one, this holds true even for fractions with fractions in the numerator (value on top of the fraction bar) and denominator (value under the fraction bar).

$\frac{\frac{a+b}{c}}{\frac{a+b}{c}}+\frac{\frac{b-a}{c}}{\frac{a-b}{c}}$

$\frac{\frac{a+b}{c}}{\frac{a+b}{c}}+\frac{\frac{-(a-b)}{c}}{\frac{a-b}{c}}$

$1+(-1)=0$

$1-1=0$

$0=0$

7 0

3 years ago

I need the answer asap

Anna71 [15]

Answer:

it's B

Step-by-step explanation:

the easiest why to tell is that, the slope intercept form y=mx+b is the form the equations are b is the y-intercept. If you look at the graph it crosses y at +16 not -16

5 0

3 years ago