А B P M S Which ones are congruent

Please need help on this question thanks. see the screenshot

slava [35]

Check the picture below.

F = sales for Friday

we know that the total of weekend sales for Germany was F + 317 + 405.

we also know that 405 is really 37.19% of that amount, say "x", which is the 100%, so

$\begin{array}{ccll} amount&\%\\ \cline{1-2} 405&37.19\\ x&100 \end{array}\implies \cfrac{405}{x}=\cfrac{37.19}{100}\implies 40500=37.19x \\\\\\ \cfrac{40500}{37.19}=x\implies 1089~\approx ~ x \\\\[-0.35em] ~\dotfill\\\\ \stackrel{friday}{F} + \stackrel{sat/sun}{317} + \stackrel{monday}{405} \approx 1089\implies F +722 \approx 1089\implies \boxed{F\approx 367}$

6 0

2 years ago

Colin invests £4300 into his bank account.

Triss [41]

To do this you need to do 4300 x 1.04 to the power of 3

4 0

3 years ago

During a period of 11 years 737737 of the people selected for grand jury duty were sampled, and 6868% of them were immigrants.

Galina-37 [17]

The formula to set out the lower and the upper margin of a confidence interval when given the proportion (no standard deviation) is

Lower margin = p - Z* √[(pq) ÷ n]
Upper margin = p + Z* √[(pq) ÷ n]

Where:
p is the sample proportion
q is 1 - p
Z* is the z-score for the confidence level
n is the number size
--------------------------------------------------------------------------------------------------------------

p = (68% of 737) ÷ 737 = 501.16 ÷ 737 = 0.68
q = 1 - p = 1 - 0.68 = 0.32
Z* = 2.58 (refer to the table attached below)
n = 737

substituting these values into the formula, we have

lower margin = 0.68 - (2.58) √[(0.68×0.32) ÷ 737]
lower margin = 0.68 - (2.58) √(0.0002952510176...)
lower margin = 0.68 - 0.04433180431
lower margin = 0.6357 (rounded to four decimal places)
lower margin = 63.57%

upper margin = 0.68 + 0.04433180431
upper margin = 0.7243 (rounded to four decimal places)
upper margin = 72.43%

The confidence interval is between 63.57% and 72.43%. In other words, we can say that between 63.57% and 72.43% of jury members are immigrant.

The claim of 69.46% is within the confidence interval, hence we can conclude that the selection of grand jury duty is not biased against the immigrant.