9514 1404 393
Answer:
5 seconds
Step-by-step explanation:
Suppose the front parts of the trains meet at point A. Since both are the same length and traveling the same speed, each will pass point A in time ...
time = distance/speed
time = (1/18 mi)/(40 mi/h) = (1/720 h) × (3600 s)/(1 h) = 5 s
That is, the rear part of each train will be at point A 5 seconds after the front part.
The rear parts will pass each other 5 seconds after the front parts meet.
Answer:
b=-25
Step-by-step explanation:
10= -2/5b
10= -2/5b
------ -------
-2/5 -2/5b
b=-25
Check:
-2/5(-25)=10
10=10
0.85$ for 1 cups
1$ for 1/0.85 cups
55.25$ for [1/0.85]*55.25 = 55.25/0.85 = 65 cups
Answer:
c
Step-by-step explanation:
