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Gala2k [10]
3 years ago
13

The length of a rectangle is 12 feet. the width of the rectangle is (1)/(2) the length. what is the perimeter of the rectangle i

n feet?
18
24
30
36
72
Mathematics
1 answer:
madreJ [45]3 years ago
4 0

Answer:

36 feet

Step-by-step explanation:

width is 12/2 or 6

12(2) + 6(2) = 36

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90 minus 10x<br><br> ill give 25 points and brainiest
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nikklg [1K]
The next 3 terms would be: -14, -17, and -20 (the pattern is your -3 each time) the 100th term would be -279 i think because there is 93 spots left after the first 7 terms, so 93 x -3 = -279
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3 years ago
If f(x) =7x+5/3-x, then show that fof power -1(x) is an identity function ​
Irina-Kira [14]

If f(X)= 7x +5/3 - x =6x +5/3

y= 6x +5/3

6x= y-5/3

f^-1(y)=x=(y-5/3)/6

So we can write

f(f^-1(y))= f((y-5/3)/6) = 6 (y-5/3)/6 +5/3= y-5/3+5/3= y

The same result can be obtained for f^-1(f(x))=x

If the function is f(x)= 7x +5/(3-x) then it is not invertible since it is not injective (pictures)

4 0
3 years ago
More on Areas. Farmer Jones, and his wife, Dr. Jones, both mathematicians, decide to build a fence in their field to keep the sh
Olin [163]

Answer:

Area covered by the fences will be 16.1 unit²

Step-by-step explanation:

Let the first parabola is represented by the function f(x) = 6x²

and second parabola by g(x) = x² + 9

point of intersection of the graphs will be determined when f(x) = g(x)

6x² = x² + 9

5x² = 9

x² = 1.8

x = ± 1.34

Now we will find the area between these curves drawn on the graph.

Area = \int_{-1.34}^{1.34}[f(x)-g(x)]dx=\int_{-1.34}^{1.34}[6x^{2}-(x^{2}+9)]dx

= \int_{-1.34}^{1.34}(5x^{2}-9)dx

= [\frac{5}{3}x^{3}-9x]_{-1.34}^{1.34}

= [\frac{5}{3}(-1.34)^{3}-9(-1.34)-\frac{5}{3}(1.34)^{3}+9(1.34)]

= [-4.01+12.06-4.01+12.06]

= 16.1 unit²

6 0
3 years ago
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