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2 years ago

1+4.25n+3/2p-3+(-2p)+5/4n

Mathematics

1 answer:

alex41 [277]2 years ago

3 0

Answer:

11/2n+-1/2p-2

Step-by-step explanation:

simplification

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What is the relationship between 10c7 and 10c3

sattari [20]

Answer:

Step-by-step explanation:

10c^3 * c^4 = 10c^7

When two numbers raised to a power are multiplied, their exponents are added

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2 years ago

A taxi travels 25 kilometers east of an airport. Then it travels from that point to a point that is 40 kilometers west of the ai

kati45 [8]

25km east + 25km return+ 40km west + 40km return = 130km

Hope that helped :)

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3 years ago

Imani spent half of her weekly allowance playing mini-golf. To earn more money, her parents let her wash the car for $4. What is

joja [24]

Answer:

$16

Step-by-step explanation:

This method is probbaly working backwards. I'm not sure.

12 - 4 = 8 (How much she was left with if she didn't wash the car for 4 dollars)

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2 years ago

A pair of shoes that normally sells for $74.88 goes on sale for 25% off. What is the sale price?

igor_vitrenko [27]

Answer:

$56.16

Step-by-step explanation:

74.88 times 0.75 =56.16

3 0

3 years ago

Read 2 more answers

The number of failures of a testing instrument from contamination particles on the product is a Poisson random variable with a m

Mazyrski [523]

Answer:

The probability that the instrument does not fail in an 8-hour shift is $P(X=0) \approx 0.8659$

The probability of at least 1 failure in a 24-hour day is $P(X\geq 1 )\approx 0.3508$

Step-by-step explanation:

The probability distribution of a Poisson random variable X representing the number of successes occurring in a given time interval or a specified region of space is given by the formula:

$P(X)=\frac{e^{-\mu}\mu^x}{x!}$

Let X be the number of failures of a testing instrument.

We know that the mean $\mu = 0.018$ failures per hour.

(a) To find the probability that the instrument does not fail in an 8-hour shift, you need to:

For an 8-hour shift, the mean is $\mu=8\cdot 0.018=0.144$

$P(X=0)=\frac{e^{-0.144}0.144^0}{0!}\\\\P(X=0) \approx 0.8659$

(b) To find the probability of at least 1 failure in a 24-hour day, you need to:

For a 24-hour day, the mean is $\mu=24\cdot 0.018=0.432$

$P(X\geq 1 )=1-P(X=0)\\\\P(X\geq 1 )=1-\frac{e^{-0.432}0.432^0}{0!}\\\\P(X\geq 1 )\approx 0.3508$

3 0

3 years ago