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2 years ago

1+4.25n+3/2p-3+(-2p)+5/4n

Mathematics

1 answer:

alex41 [277]2 years ago

3 0

Answer:

11/2n+-1/2p-2

Step-by-step explanation:

simplification

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Can someone help me with this?

Oduvanchick [21]

Answer:

Equation

Step-by-step explanation:

Equation Rate of change: 2/1=2

Graph Rate of Change: -4/1=-4

8 0

3 years ago

Read 2 more answers

g A 5 foot tall man walks at 10 ft/s toward a street light that is 20 ft above the ground. What is the rate of change of the len

vredina [299]

Answer:

$-\frac{10}{3}ft/s$

Step-by-step explanation:

We are given that

Height of man=5 foot

$\frac{dy}{dt}=-10ft/s$

Height of street light=20ft

We have to find the rate of change of the length of his shadow when he is 25 ft form the street light.

ABE and CDE are similar triangle because all right triangles are similar.

$\frac{20}{5}=\frac{x+y}{x}$

$4=\frac{x+y}{x}$

$4x=x+y$

$4x-x=y$

$3x=y$

$3\frac{dx}{dt}=\frac{dy}{dt}$

$\frac{dx}{dt}=\frac{1}{3}(-10)=-\frac{10}{3}ft/s=-\frac{10}{3}ft/s$

Hence, the rate of change of the length of his shadow when he is 25 ft from the street light= $-\frac{10}{3}ft/s$

7 0

2 years ago

What is rt5 x rt3<br> yeah do that plz

sergij07 [2.7K]

Answer:

3(2r+1)

Step-by-step explanation:

5r+1 is 6

Then you factor out 3 and get 3(2r+1)

7 0

2 years ago

Can someone help me please.

Sholpan [36]

Answer:hello

Step-by-step explanation:

7 0

3 years ago

For the given values of n and d, find integers q and r such that n = dq + r and 0 ≤ r < d. n = −67, d = 8

Firlakuza [10]

Answer:

$q = 8$

$r = 3$

Step-by-step explanation:

Given

$n = dq + r$

$0 \le r < d$

$n = 67$ --- not -67

$d = 8$

Required

Find q and r

Substitute values for d and b

$n = dq + r$

$67 = 8 * q + r$

$67 = 8q + r$

Make q the subject

$q = \frac{67 - r}{8}$

$0 \le r < d$ means that r is less than 8 but greater than or equal to 0

And r and q are integers.

Let $r = 3$

$q = \frac{67 - 3}{8}$

$q = \frac{64}{8}$

$q = 8$

No other true values of r and q can be gotten.

7 0

2 years ago