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inysia [295]
3 years ago
9

Find the missing lengths: LO=5 and OK=4, find OH and KH.

Mathematics
2 answers:
hodyreva [135]3 years ago
8 0

Answer:

The length of KH is 6 units and OH is 6.3 units.

Step-by-step explanation:

Given the figure with lengths LO=5 and OK=4. we have to find the length of  OH and KH.

In ΔLOH

By Pythagoras theorem

LH^2=LO^2+OH^2\\\\LH^2=5^2+OH^2 → (1)

In ΔKOH,

KH^2=OH^2+OK^2\\\\KH^2=OH^2+4^2  → (2)

In ΔKHL,

KL^2=LH^2+KH^2

Using eq (1) and (2), we get

KL^2=5^2+OH^2+OH^2+4^2

9^2=25+2OH^2+16

⇒ 2OH^2=81-25-16=40

⇒ OH=\sqrt{20}=6.324\sim6.3units.

Put the above value in eq 2, we get

KH^2=20+4^2=36

⇒ KH=6 units.

Naddika [18.5K]3 years ago
4 0

Answer:

KH = 6, OH = \sqrt{20}

Step-by-step explanation:

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