Answer:
The hawk reaches the rabbit at t=4.3 sec
Step-by-step explanation:
Let
h ----> is the height in feet
t ----> is the time in seconds
v ---> the initial velocity in feet pr second
s ----- is the starting height
we have
when the hawk reaches the rabbit the value of h is equal to zero
we have
substitute
Solve the quadratic equation by graphing
The solution is t=4.3 sec
see the attached figure
A) y= -2, 3, 7
B) y= 8, 0, -6
C) y= -8, 1, 7
d) y= 1, -2, -6
If we have two points;
A(x₁,y₁)
B(x₂,y₂)
m=slope
m=(y₂-y₁) / (x₂-x₁)
Therefore:
(6,7)
(9,2)
m=(2-7) / (9-6)=-5/3.
Solution₁= the solpe of the line that passes through the poitns (6,7) and (9,2) is m=-5/3.
(17,9)
(5,29)
m=(29-9) / (5-17)=20/-12=-5/3
Solution ₂: the slope of the line that passes through the parir of points (17,9) and (5,29) is m=-5/3
Therefore, both lines have the same slope.
Answer:
B
Step-by-step explanation:
i know
Answer:
10^0*10^1-1,
10^0*10^1*1^10,
10^0+10^1*1^10,10^0+10^1+1^10
Step-by-step explanation:
