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NeTakaya
3 years ago
14

Write an expression: Jim earned “j” in tips, and Steve earned “s” in tips. They combined their tips and then split them equally.

Mathematics
1 answer:
inessss [21]3 years ago
5 0

Answer:

(j + s) /2

Step-by-step explanation:

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Suppose a triangle has two sides of length 3 and 4 and that the angle
rodikova [14]

Answer:

B

Step-by-step explanation:

We can use the law of cosinse:

c^{2} = a^{2} + b^{2} − 2ab cos(C)

Suppose the two sides are a and b, and the angle betweent them is C.

c^{2} = 3^{2} + 4^{2} − 2*3*4 cos(60)

We can simplify this to get c^{2} =25-12=13

c=\sqrt{13}

Answer choice B

4 0
2 years ago
Read 2 more answers
1.)12.5+(-31.5)=<br>2.)-31.91+(-16.7)=<br>3.)1/6+(-11/12)+2/3=<br>4.)29+(-15.7)+(-31.05)=
Xelga [282]
1. = Step 1. Simplify Brackets and you get 12.5 - 31.5 Step 2. Simplify and you get -19&#10; which is your answer.

2. = Step 1. Simplify Brackets and you get -31.91-16.7 Step 2. Simplify and you get -48.61

3. = Step 1. Simplify Brackets and you get \frac{1}{6} - \frac{11}{12} + \frac{2}{3} Step 2. Simplify and you get - \frac{1}{12}

4. Step 1. = Simplify Brackets and you get 29-15.7-31.05 Step 2. Simplify and you get -17.75
5 0
4 years ago
Solve sin x = cos x on the closed interval [pi, 3pi/2].​
Gwar [14]

Answer: x=5π/4

Step-by-step explanation:

sin x = cos x

sin^2 x=cos^2 x

sin^2 x+sin^2 x=cos^2 x+sin^2x

2 sin^2 x=1

sin^2 x=1/2

sin x=(1/2)^1/2

sin x=\frac{\sqrt{2}}{2}

x=45 degrees, 225 degrees

x=180/4, 5(180)/4

x=π/4, 5π/4 ==> π<=x<=3π/2

x=5π/4

5 0
1 year ago
Estimate the answer of the problem 314 + 592
Radda [10]

There are two ways you could do this.

1) 314 is about 310. 592 is about 590. So 310 + 590 = 900.

314 + 592 ≈ 900.

2) 314 is about 300. 592 is about 600. So 300 + 600 = 900.

314 + 592 ≈ 900.

6 0
3 years ago
Read 2 more answers
It is possible to prove congruency of two triangles by comparing the size of corresponding angles only
Leno4ka [110]
Nope because congruent triangles mean directly equal to. two triangles can have the same angles but unequal lengths, hence congruency cannot be proven by using angles only
7 0
3 years ago
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