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Zina [86]
1 year ago
13

Solve sin x = cos x on the closed interval [pi, 3pi/2].​

Mathematics
1 answer:
Gwar [14]1 year ago
5 0

Answer: x=5π/4

Step-by-step explanation:

sin x = cos x

sin^2 x=cos^2 x

sin^2 x+sin^2 x=cos^2 x+sin^2x

2 sin^2 x=1

sin^2 x=1/2

sin x=(1/2)^1/2

sin x=\frac{\sqrt{2}}{2}

x=45 degrees, 225 degrees

x=180/4, 5(180)/4

x=π/4, 5π/4 ==> π<=x<=3π/2

x=5π/4

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3 years ago
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3 years ago
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3 years ago
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Answer:

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