Answer: it’s 6:00 pm
Step-by-step explanation:
Answer:
The density of the bar of gold is 19.32 grams per cubic centimeter .
Step-by-step explanation:
Formula

As given
A bar of gold has a volume of 722 cubic centimeters and weighs 13.949 kilograms.
As 1 kilogram = 1000 gram
Than convert 13.949 kilograms into grams.
13.949 kilograms = 13.949 × 1000 grams
= 13949 grams
Mass = 13949 grams
Volume = 722 cubic centimeter
As put in the formula

Density = 19.32 grams per cubic centimeter (Approx)
Therefore the density of the bar of gold is 19.32 grams per cubic centimeter .
Distributive property, since 3(2x) you distribute and get 6x
Given:
- Height of cylinder is 18.2 cm
- Radius of cylinder is 3 cm

To Find?

Solution:
Using formula:
- Surface area of cylinder = 2πr (h + r)

Substituting values in the formula:





- Hence, (B) 399.4 cm² is right answer.