Point R is the midpoint of FE¯¯¯¯¯ , so the coordinates of point R are (3a, b).
In △DEF , the length of the base, DF¯¯¯¯¯ , is
4a, and the height is 2b, so its area is
1/2×4a×2b = 4ab.
In △QRP , the length of the base, QR¯¯¯¯¯ , is
3a-a = 2a, and the height is b, so its area is 1/2×2a×b = ab .
Comparing the expressions for the areas proves that the area of the triangle created by joining the midpoints of an isosceles triangle is one-fourth the area of the larger isosceles triangle.
Answer:
all work is shown and pictured
Answer:
To find area of parallelogram, multiply base and height
Step-by-step explanation:
Base is 6, height is 4
6 x 4 = x
x = 24
3 because the x value has been repeated
They got paid the same amount. If you divide 417.96 and 27, you get 15.48. And if you divide 495.36 and 32 you get 15.48.
I hope that helped you.
