Answer, step-by-step explanation:
A. With the previous exercise we can deduce that there is the situation of a number of sales in a grocery store, the relative frequency for the number of units sold, is shown below:
units sold. relative frequency. Acumulative frequency. interval of random numbers
30. 0.16. 0.16. 0.00 <0.16
40. 0.24. 0.4. 0.16 <0.4
50. 0.3. 0.7. 0.4 <0.7
60. 0.2. 0.9. 0.7<09
70. 0.1. 1. 0.9<1
B. For the next point, they give us some random numbers and then it is compared with the simulation of 10 days in sales:
random Units
number. sold
0.12. 30
0.96. 70
0.53. 50
0.80. 60
0.95. 70
0.10. 30
0.40. 50
0.45. 50
0.77. 60
0.29. 40
the two lists are compared so that opposite each one is the result of the simulation
Remember
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aw, latex is being uncoorporative right now
anyway
(a/b)^c=(a^c)/(b^c)
so
(4/5)^6=(4^6)/(5^6)=4096/15625
Answer:
20% or . 2
Step-by-step explanation:
To understand how to solve, you have to understand that 14 can go into 70 (X) amount of times, this is how percentages work. To find how many times 14 goes into 70, you divide 14/70 = .20
Since 14 is 20% of 70, you can multiply 14 by 5 and it equals a 100% of 70, or just 70 itself. Hope this helped
You could divide 100 by 4 which is 25. Then divide 69 by 4 which would bring you to 17.25. 169 divided by 4 is 42.25. The answer would be 42 with a remainder of 1
Here are the numbers that represent each based on the box plot:
Median: 11 (located at the vertical line in the middle of the box)
Range: 19 - 7 = 12 (highest value - lowest value)
25%: 9 (at the left end of the box)
75%: 14 (at the right end of the box)
Interquartile range: 14 - 9 = 5 (the distance from the beginning to the end of the middle half of the data)
