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ddd [48]
3 years ago
8

Can someone plz help me ASAP!!!

Mathematics
1 answer:
anastassius [24]3 years ago
7 0
I would honestly pick c or d
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Find the solution(s) to the system of equations. Select all that apply.<br> y=x² - 4<br> y = -x-2
Andrej [43]

Answer:

x=1, y= -3

x= -2 y=0

Step-by-step explanation:

5 0
3 years ago
Answer choices:
pychu [463]

Answer:

B. 15

Step-by-step explanation:

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5/40 × 120 = 15

4 0
3 years ago
What does it mean that the fan data are numerical and univariate?
VikaD [51]

haven't heard these terms before....BUT....

Step-by-step explanation:

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5 0
3 years ago
A conical tent made of canvas has a base that is 34 feet across and a slant height of 12 feet. To the nearest whole unit, what i
tresset_1 [31]
Here you'll need to do some online research, using "area of a cone" as your search term.  There is a formula!  But it's complicated.

Once you've found this formula online, substitute 17 feet for r.  The height of the cone has to be calculated from the slant height (these are not the same):

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The area of the base is pi*r^2, or pi*17^2 square feet.
4 0
3 years ago
Read 2 more answers
Consider this equation. Cos(0) = 8/9 if 0 is an angle in quadrant IV, what is the value of tan(0)? I
Vinvika [58]

Answer:

\displaystyle \tan(\theta)=-\frac{\sqrt{17}}{8}

Step-by-step explanation:

We are given that:

\displaystyle \cos(\theta)=\frac{8}{9}

Where θ is in QIV.

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Recall that cosine is the ratio of the adjacent side over the hypotenuse.

Therefore, the opposite side is:

o=\sqrt{9^2-8^2}=\sqrt{17}

Next, in QIV, only cosine is positive: sine and tangent are both negative.

Tangent is the ratio of the opposite side to the adjacent. So:

\displaystyle \tan(\theta)=\frac{\text{opposite}}{\text{adjacent}}

Substitute. Tangent is negative in QIV. Hence:

\displaystyle \tan(\theta)=-\frac{\sqrt{17}}{8}

3 0
3 years ago
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