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Ahat [919]
3 years ago
9

What is an explicit formula for the geometric sequence 64,16,4,1,... where the first term

Mathematics
1 answer:
olya-2409 [2.1K]3 years ago
7 0

Answer:

A

Step-by-step explanation:

The explicit formula for a geometric sequence is

f(n) = f(1) (r)^{n-1}

where f(1) is the first term and r the common ratio

Here f(1) = 64 and r = \frac{f(2)}{f(1)} = \frac{16}{64} = \frac{1}{4} , then

f(n) = 64 (\frac{1}{4}) ^{n-1} → A

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∠ and ∠ are supplementary angles. If ∠ = (2 − 30)° and ∠ = 4, find the measure of the larger angle
Gala2k [10]

Answer:

We get ∠A =40° and ∠B = 140° and ∠B = 140° is measure of larger angle

Step-by-step explanation:

we have  ∠A = (2x − 30)° and ∠B = 4x, and we need to find measure of larger angle. And ∠A and ∠A are supplementary angles.

If the angles are supplementary there sum is equal to 180° i.e ∠A + ∠B = 180°

So,  First we have to find the value of x. and then we can determine larger angle.

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6x-30=180

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So, value of x is x=35

Now finding ∠A and ∠B

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6 0
3 years ago
Three molecules of type A, three of type B, three of type C, and three of type D are to be linked together to form a chain molec
ipn [44]

Answer:

a) 369,600

b) 0.0000649

Step-by-step explanation:

If all of the A's, B's, C's and D's were different, the number of ways to form a molecule would be calculated as n!. However, given that every molecule is repeat 3 times, we need to reduce the number dividing by 3! for every type of molecule.

It means that the number of ways in which we can organize n elements where not all of them are equal is calculated as:

\frac{n!}{n_1!*n_2!*...*n_k!}

Where k is the number of elements that are differents and n_1,n_2,...,n_k are the number of times that every element appears.

Now, we have 4 different types of molecules (A,B,C,D) so k is equal to 4. Additionally, there are 3 molecules of type A, 3 of type B, 3 of type C, and 3 of type D, so n_1=3, n_2=3, n_3=3 and n_4=3. It means that there are 369,600 ways to form chain molecules and it is calculated as:

\frac{12!}{3!*3!*3!*3!}=369,600

Now, the number of ways where all three molecules of each type end up next to one another is calculated as:

4*3*2*1=24

Because, first we have 4 possible types of molecules to occupy the first three positions, then we have 3 possible types of molecules to occupy the following 3 positions, then we have 2 possible types of molecules and finally we have 1 possible type of molecule

So, the probability that all three molecules of each type end up next to one another is calculated as:

\frac{24}{369600}=0.0000649

6 0
3 years ago
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