2 years ago

The weight of an object on the moon is

Mathematics

1 answer:

alexgriva [62]2 years ago

8 0

Answer:

1/6 = 0.16 = 16%

restate the question: 16% of 20.5 is what? multiply: 20.5*.16 = 3.28 now, to find the weight of the object on the moon, subtract 16% from 20.5. 16% of 20.5 is 3.28 20.5-3.28 = 17.22 = 17 22/100 = 17 11/50

the weight of the object is 17 11/50 pounds on the moon.

You might be interested in

Hi plz answer I problem I have a class plz

Aleonysh [2.5K]

He still has 83 miles to travel

4 0

2 years ago

O picatura de ulei cu volumul de 0,3 mm a format pe suprafata apei o pelicula cu aria de 300 cm Calculati grosimea peliculei

lesantik [10]

What did you misspell something or are you foreign

8 0

3 years ago

Okay hear this someone came into my shop and stole $100 without my knowledge they came back to the store and spent $70 in items

hodyreva [135]

You lost thirty dollars

4 0

3 years ago

Read 2 more answers

Help me with this please

nalin [4]

This is incorrect. X can be negative, making the expression on the left less than 0. If x were -10, then:
3 x -10 + 1 > 0
-30 + 1 > 0
-29 > 0
Is NOT true.

5 0

3 years ago

The perimeter of a rectangle is 16.6km, and its area is 13.42km2. Find its length and width. length : km width : km

Otrada [13]

Answer:

l=5.12 & w=2.62

Step by step explanation:

A=l×w

13.42=lw

w=13.42/l

$p = 2(l + w) \\ 16.6 = 2(l + \frac{13.42}{l} ) \\ 16.6 = 2( \frac{ {l}^{2} + 13.42}{l}) \\ 16.6 = 2(l + 13.42) \\ 16.6 = 2l + 26.84 \\ 2l = 26.84 - 16.6 \\ 2l = 10.24 \\ l = \frac{10.24}{2} \\ l = 5.12km$

Since you have found the value of the length you can find the value.of the width.

$w = \frac{13.42}{l} \\ w = \frac{13.42}{5.12} \\ w = 2.62km$

5 0

3 years ago