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Veseljchak [2.6K]
2 years ago
7

What is 3/4 divided by 1/3?

Mathematics
1 answer:
GalinKa [24]2 years ago
6 0

Answer:

1/4

Step-by-step explanation:

have a good day!

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Rewrite 0.37 in expanded form using powers of ten.
Black_prince [1.1K]

Expanded form is the form of writing numbers in addition. Example: 653 would be 600+50+3 in expanded form. .37 using powers would be 37×10^-2 .

In expanded form, we just need to expand the 37 because it is the only one with 2 different places without a 0 in either one.

Answer: 30+7×10^-2 would be the expanded form of .37 using powers of 10.

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a 5 inch tall bamboo shoot doubles in height every 3 days. if the equation, y=ab^x where x is the number of doubling periods, re
Lemur [1.5K]
X-doubling periods
Y-height of bamboo
Y=ab^x

1) make a table of values
X Y
1 5
2 10
3 20

2) write equations and substitute
5=ab^1 —> a=5/b^1 —> a=5/b
10=ab^2

Substitute into second equation

10=(5/b)*b^2
10=5b^2/b
10=5b
b=2

Substitute back in

b=2
10=a*2^2
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End equation:
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3 0
3 years ago
The table show the age in years of employees in a company
adelina 88 [10]

Answer:

A. 24 ≤ a < 26.

B. 22.5

Step-by-step explanation:

A. Determination of the modal class interval.

Mode is the class with the highest frequency.

From the table given above, the highest frequency is 8, therefore the class will the highest frequency is:

24 ≤ a < 26.

B. To obtain the mean, we must determine the class mark. This is illustrated below:

Class >>>>> class mark >>> frequency

18 – 19 >>>> 18.5 >>>>>>>>> 3

20 – 21 >>> 20.5 >>>>>>>> 2

22 – 23 >>> 22.5 >>>>>>>> 7

24 – 25 >>> 24.5 >>>>>>>> 8

26 >>>>>>>> 26 >>>>>>>>> 0

The mean is given by the summation of the product of the class mark and frequency divided by the total frequency. This is illustrated below:

Mean = [(18.5x3) + (20.5x2) + (22.5x7) + (24.5x8) + (26x0)] / (3+2+7+8+0)

Mean = (55.5 + 41 + 157.5 + 196 + 0)/20

Mean = 450/20

Mean = 22.5

Therefore, the mean age is 22.5

4 0
2 years ago
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