The optimum shape of such a box is half a cube. The corresponding cube will have a volume of 2×256 ft³ = 512 ft³ = (8 ft)³. Such a box has a square base that is 8 ft on a side. If the height is half that of the cube, it will be 4 ft.
The dimensions of your box will be 8 ft square by 4 ft high.
_____
If the base dimension is x ft, the area (quantity of material) is
... a = x² + 4x(256/x²)
... a = x² + 1024x⁻¹
Then the derivative of area with respect to x is
... a' = 2x -1024x⁻²
Setting this derivative to zero and solving for x gives the value of x for minimum area.
... 0 = 2x -1024/x²
... 512 = x³
... x = 8 . . . . . . . . same as above.
It is 12:04 when she arrives at the library. Add 50 mins to equal 12:54. Then add 4 to equal 12:56. She leaves at 12:56.
21/72
then simplified
= 7/24
Just finished the test :D. The answer would be -31 1/3
HOPE THIS HELPS :D
Answer:
<u>The lengths of side A is 22.4 and B is 11.9</u>.
Step-by-step explanation:
Given:
If side A is twice as long as B and C is 25 using the Pythagorean Theorem.
Now, to find the lengths of side A and B.
Let the side B be 
So, the side A be 
Side C = 25.
Now, to solve by using Pythagorean Theorem:
A² + B² = C²
<em>Dividing both sides by 5 we get:</em>
<em>Using square root on both sides we get:</em>
<u>B rounding to the nearest tenth = 11.9.</u>
Now, to get A by substituting the value of 
:
<u>A rounding to the nearest tenth = 22.4.</u>
Therefore, the lengths of side A is 22.4 and B is 11.9.
