I will give Brainiest if you are right
2 answers:
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<u>QUESTION 1</u>
The given system of equation is
and
Let us substitute equation (1) into equation (2) to get,
We expand the bracket to get,
We simplify to get.
We group like terms to get
We now substitute in to equation (1) to obtain,
The correct answer is option A.
<u>QUESTION 2</u>
The given system of equations is
and
We make y the subject in equation (2) to get,
We put equation (3) into equation (1) to obtain,
We group like terms to get,
This implies that,
We divide through by to get,
Hence the x-coordinate is
<u>QUESTION 3</u>
The given system is
and
We make the subject in equation (2) to get,
We put equation (3) into equation (1) to obtain,
We expand the bracket to get,
Group like terms to get,
We simplify to get;
This implies that,
Therefore the y-coordinate is 14.
I made my own graph using the given points. Pls. see attachment.
<span>Part A: Using the graph above, create a system of inequalities that only contains points D and F in the overlapping shaded regions. Explain how the lines will be graphed and shaded on the coordinate grid above.
I used paint program to graph the points based on the given data.
I used a ruler as guide as I draw my line containing both points D and F and extended the line outward.
The yellow lines above represents the shaded portion of the graph.
y = mx + b
b is the y-intercept. It is the value of y when x is 0. In this case, b = 3.5
m is the slope. It is the change in y divided by the change in x.
point D (2,4) ; point F (-2,3)
change in y: 4 - 3 = 1
change in x: 2 - (-2) = 4
m = 1/4
y = 1/4 x + 3.5
Since we are looking for a system of inequality and the portion shaded is in the upper part of the line, the value of y will be greater than or equal to.
y </span>≥ 1/4x + 3.5<span>
Part B: Explain how to verify that the points D and F are solutions to the system of inequalities created in Part A.
To check the solution given above. We will use the x values of points D and F and check whether its y values are equal to or greater than the solution.</span>
y ≥ 1/4x + 3.5
Point D (2,4) : x = 2 : y ≥ 1/4 * 2 + 3.5 → 0.5 + 3.5 → 4
Point F (-2.3): x = -2 ; y ≥ 1/4 * -2 + 3.5 → -0.5 + 3.5 → 3
<span>
Part C: Chickens can only be raised in the area defined by y > 2x − 2. Explain how you can identify farms in which chickens can be raised.
y > 2x - 2
We will get the coordinates of each point and see if its x value will generate the desired value of y.
A(2,-3) ; x = 2 : </span><span>y > 2(2) - 2 </span>→ 4 - 2 → 2 . DID NOT PASS. -3 is lesser than 2.<span>
B(-3,-4) ; x = -3 : y > 2(-3) - 2 </span>→ -6 - 2 → -8. PASSED. -4 is greater than -8.<span>
C(-4,2) ; x = -4 : y > 2(-4) - 2 </span>→ -8 - 2 → -10. PASSED. 2 is greater than -10.<span>
D(2,4) ; x = 2 : y > 2(2) - 2 </span>→ 4 - 2 → 2. PASSED. 4 is greater than 2.<span>
E(3,1) ; x = 3 : y > 2(3) - 2 </span>→ 6 - 2 → 4. DID NOT PASS. 1 is lesser than 4.<span>
F(-2,3) ; x = -2 ; y > 2(-2) - 2 </span>→ -4 - 2 → -6. PASSED. 3 is greater than -6.
Among the farms, points B,C, D, and F can raise chickens based on the given system of linear inequality.
<span>Part A: Using the graph above, create a system of inequalities that only contains points D and F in the overlapping shaded regions. Explain how the lines will be graphed and shaded on the coordinate grid above.
I used paint program to graph the points based on the given data.
I used a ruler as guide as I draw my line containing both points D and F and extended the line outward.
The yellow lines above represents the shaded portion of the graph.
y = mx + b
b is the y-intercept. It is the value of y when x is 0. In this case, b = 3.5
m is the slope. It is the change in y divided by the change in x.
point D (2,4) ; point F (-2,3)
change in y: 4 - 3 = 1
change in x: 2 - (-2) = 4
m = 1/4
y = 1/4 x + 3.5
Since we are looking for a system of inequality and the portion shaded is in the upper part of the line, the value of y will be greater than or equal to.
y </span>≥ 1/4x + 3.5<span>
Part B: Explain how to verify that the points D and F are solutions to the system of inequalities created in Part A.
To check the solution given above. We will use the x values of points D and F and check whether its y values are equal to or greater than the solution.</span>
y ≥ 1/4x + 3.5
Point D (2,4) : x = 2 : y ≥ 1/4 * 2 + 3.5 → 0.5 + 3.5 → 4
Point F (-2.3): x = -2 ; y ≥ 1/4 * -2 + 3.5 → -0.5 + 3.5 → 3
<span>
Part C: Chickens can only be raised in the area defined by y > 2x − 2. Explain how you can identify farms in which chickens can be raised.
y > 2x - 2
We will get the coordinates of each point and see if its x value will generate the desired value of y.
A(2,-3) ; x = 2 : </span><span>y > 2(2) - 2 </span>→ 4 - 2 → 2 . DID NOT PASS. -3 is lesser than 2.<span>
B(-3,-4) ; x = -3 : y > 2(-3) - 2 </span>→ -6 - 2 → -8. PASSED. -4 is greater than -8.<span>
C(-4,2) ; x = -4 : y > 2(-4) - 2 </span>→ -8 - 2 → -10. PASSED. 2 is greater than -10.<span>
D(2,4) ; x = 2 : y > 2(2) - 2 </span>→ 4 - 2 → 2. PASSED. 4 is greater than 2.<span>
E(3,1) ; x = 3 : y > 2(3) - 2 </span>→ 6 - 2 → 4. DID NOT PASS. 1 is lesser than 4.<span>
F(-2,3) ; x = -2 ; y > 2(-2) - 2 </span>→ -4 - 2 → -6. PASSED. 3 is greater than -6.
Among the farms, points B,C, D, and F can raise chickens based on the given system of linear inequality.