Answer: provided in the explanation segment
Step-by-step explanation:
(a). from the question, we can see that since that б is known, we can use standard normal, z.
we are asked to find an 80% confidence interval for the average weights of Allen's hummingbirds in the study region. What is the margin of error?
⇒ 80% confidence interval for the average weight of Allen's hummingbirds is given thus;
x ± z * б / √m
which is
3.15 ± 1.28 * 0.32/√10
= 3.15 ± 0.1295 = 3.0205 or 3.2795
(b). normal distribution of weight (c) б is known
(c). option (a) and (e) are correct
(d). from the question, let sample size be given as S
this gives';
1.28 * 0.32/√S = 0.15
√S = (1.28 * 0.32) / 0.15 = 2.73
S = 7.4529
cheers i hope this helps
Answer:
6.5%
Step-by-step explanation:
Percentage error formula =
|Estimated value - Real value|/Real value × 100
From the above question,
Estimated value = 17,466
Real value = 16,400
Percentage error = |17,466 - 16,400|/16,400 × 100
= 1066/16,400 × 100
= 0.065 × 100
= 6.5%
Therefore, the percent error = 6.5%
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Answer:
The -7 changes to 7 and the ordered pair of the new point is (4,7)
The -2 changes to 2 and the ordered pair of the new point is (2,-5)
Step-by-step explanation:
Hope this helped.
$0.25 you just have to multiply .65 times 5 for site A which is $3.25 and for sure b just plug in 5 for x and multiply by .60 which gives you $3.00 so site A gives you $0.25 more
