Answer:
he has to start at 8:30 PM I think
Step-by-step explanation:
it's because you do 30*5 then you get the answer 150, then you will do 150/60 whitch will get you to 2.5 and I think 2.5 is 2 hours, and 30 minutes. Then you minius 2 hours, and 30 minutes to the 10 hours and you get 8:30 PM (I don't know if that's correct or not)
There you go!! Hope it helps
Answer:
the answer is C (280 square feet)
Step-by-step explanation:
First, cut the lawn so that it becomes two shapes: a rectangle, and a triangle. Solve for both areas.
A(r) = lw
A(r) = (14)(16)
A(r) = 224 square feet
A(t) = bh/2
A(t) = (8)(14) / 2
A(t) = 112 / 2
A(t) = 56 square feet
Add the two areas:
A(r) + A(t) = Area of lawn
224 square feet + 56 square feet = 280 square feet.
Answer:
The solution is (3,13) and (-1,-3). So none of the mentioned options is correct.
Step-by-step explanation:
Given that


Now, by susbstituting the value of 'y' from equation i to equation ii, we get






Now by factorization, equation iii can be written as



x = 3 and x = -1
By putting the values of x in equation i, we get
y = 4(3) + 1
y = 12 +1
y = 13
and
y = 4(-1) + 1
y = -4 +1
y = -3
Therefore, the solution is (3,13) and (-1,-3). So none of the mentioned options is correct.
Come on now, check your book on the "product to sum" identities