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3 years ago

Solve the equation or formula for the indicated variable. T=2rh + 2r^2 ; for h

1 answer:

3 0

Ugh I hated learning these, they are so confusing

so we need to isolate the part that has h

so we would subtract 2r^2

T - 2r^2 = 2rh

the we would need to divide by 2r

(T - 2r^2)/2r = h

but we can simplify the left side

T/2r - 2r = h

I think that's right but not 100% sure

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If a=i+7j+k and b=i+11j+k, find a unit vector with positive first coordinate orthogonal to both a and

Scilla [17]

Take the cross product, then normalize the result.

$\mathbf a\times\mathbf b=\begin{vmatrix}\mathbf i&\mathbf j&\mathbf k\\1&7&1\\1&11&1\end{vmatrix}=-4\,\mathbf i+4\,\mathbf k$

This has norm

$\|\mathbf a\times\mathbf b\|=\sqrt{(-4)^2+4^2}=4\sqrt2$

and so a unit vector orthogonal to both given vectors is

$\dfrac{\mathbf a\times\mathbf b}{\|\mathbf a\times\mathbf b\|}=-\dfrac1{\sqrt2}\,\mathbf i+\dfrac1{\sqrt2}\,\mathbf k$

An equally correct answer would be the negative of this vector, since $\mathbf b\times\mathbf a=-\mathbf a\times\mathbf b$ .

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3 years ago

Help asap please i don't know the answer lol

Sveta_85 [38]

Answer:

Step-by-step explanation:

The parallel line BC divides the sides AD and AE in proportion, that is

$\frac{AB}{BD}$ = $\frac{AC}{CE}$ , that is

$\frac{2}{3}$ = $\frac{AC}{4}$ ( cross- multiply )

3AC = 8 ( divide both sides by 3 )

AC = $\frac{8}{3}$ = 2 $\frac{2}{3}$ , hence

AE = AC + CE

= 2 $\frac{2}{3}$ + 4 = 6 $\frac{2}{3}$ → H

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3 years ago

This picture shows a cube and its net

fenix001 [56]

The formula is 6 a^2

6 x (11^2)

11 x 11=121

6 x 121 = 726

So 726 is your answer

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BigorU [14]

Answer: 72

Step-by-step explanation:

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