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IgorC [24]
3 years ago
10

Ben can type 153 words in 3 minutes. At this rate, how many words can he type in 10 minutes?

Mathematics
2 answers:
jeka943 years ago
8 0

Answer:

1 minute = 51 words

10 minutes = 510

Step-by-step explanation:

you divide 153 by 3 to see how many words he can type in one minute, which is 51 words. you then multiply that answer by 10 to see how many words he can type in 10 minutes. 51 x 10 = 510, which means he can type 51 words in one minute and 510 in ten minutes.

koban [17]3 years ago
6 0
Answer: 510

Explanation
153/3 = 51

51 x 10 = 510

Hope this helped
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Number sequences 2, 12, 72, 432, 2592.... is it arithmetic, geometric, or neither?
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It is geometric because it is increasing by a common factor. If you multiply the previous number by 6 you receive the next number. If it were arithmetic you would add the number, not multiply.
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Find the absolute maximum and minimum values of the following function on the given interval. If there are multiple points in a
Bond [772]

f(x)=3\sin x+3\cos x\implies f'(x)=3\cos x-3\sin x

f has critical points where f'=0:

3\cos x-3\sin x=0\implies\cos x=\sin x\implies\tan x=1\implies x=\pm\dfrac\pi4+2n\pi

where n is any integer. We get solutions in the interval \left[0,\frac\pi3\right] for n=0, for which x=\frac\pi4.

At this critical point, we have f\left(\frac\pi4\right)=3\sqrt2\approx4.243.

At the endpoints of the given interval, we have f(0)=3 and f\left(\frac\pi3\right)=\frac{3+3\sqrt3}2\approx4.098.

So we have the extreme values

\max\limits_{x\in\left[0,\frac\pi3\right]}f=3\sqrt2

\min\limits_{x\in\left[0,\frac\pi3\right]}f=3

8 0
3 years ago
Please HELP ASAP! financial math!
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3 years ago
Which expressions represent the difference of exactly two expressions?
evablogger [386]

Answer:

  1, 3, 4

Step-by-step explanation:

Among these answer choices, you're looking for two expressions separated by a minus sign. Choice 2 is only one expression, so does not meet the required criterion.

  1. 6(x+7)-2

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7 0
3 years ago
The distribution of SAT II Math scores is approximately normal with mean 660 and standard deviation 90. The probability that 100
gayaneshka [121]

Using the <em>normal distribution and the central limit theorem</em>, it is found that there is a 0.1335 = 13.35% probability that 100 randomly selected students will have a mean SAT II Math score greater than 670.

<h3>Normal Probability Distribution</h3>

In a normal distribution with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

  • It measures how many standard deviations the measure is from the mean.
  • After finding the z-score, we look at the z-score table and find the p-value associated with this z-score, which is the percentile of X.
  • By the Central Limit Theorem, the sampling distribution of sample means of size n has standard deviation s = \frac{\sigma}{\sqrt{n}}.

In this problem:

  • The mean is of 660, hence \mu = 660.
  • The standard deviation is of 90, hence \sigma = 90.
  • A sample of 100 is taken, hence n = 100, s = \frac{90}{\sqrt{100}} = 9.

The probability that 100 randomly selected students will have a mean SAT II Math score greater than 670 is <u>1 subtracted by the p-value of Z when X = 670</u>, hence:

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{670 - 660}{9}

Z = 1.11

Z = 1.11 has a p-value of 0.8665.

1 - 0.8665 = 0.1335.

0.1335 = 13.35% probability that 100 randomly selected students will have a mean SAT II Math score greater than 670.

To learn more about the <em>normal distribution and the central limit theorem</em>, you can take a look at brainly.com/question/24663213

7 0
2 years ago
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