Answer:
do it ur self stop being lazy dang
Explanation:
Answer:
The correct answer is option d.
Explanation:
The production of Acetyl-CoA takes place by the dissociation of both carbohydrates and lipids in the process of glycolysis and beta-oxidation. It then moves into the TCA cycle in the mitochondria and combines with oxaloacetate to give rise to citrate.
In the given case, no labeling will be found in the acetyl-CoA. The labeled C3 and C4 carbon of glucose signify the carboxyl carbon of pyruvate. In the succeeding reactions of the transformation of pyruvate to acetyl-CoA, the carboxyl carbon gets lost in the form of carbon dioxide. Thus, acetyl-CoA does not comprise any labeled C3 and C4 of glucose.
To calculate the energy offered from food, multiply the number of grams of protein, carbohydrate, and fat by 4, 4, and 9, respectively.
Then add the results together.
Given: 500 grams of carbohydrates, 30 grams of protein, and 75 grams of fat in one day.
500 grams x 4 kcal/g = 2000 kcal
30 grams x 4 kcal/g = 120 kcal
75 grams x 9 kcal/g = 675 kcal
= 2795 kcal
From this data, you can calculate the percentage of k calories each of the energy nutrients give to the total.
Solution:
2000/2795 * 100% = 72% from carbohydrates
120/2795 * 100% = 4% from protein
675/2795 * 100% = 24% from fat
Total: 100%
