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2 years ago

Which expression is equivalent to (fg) (5)? F(5)* g(5) F(5)+g(5) 5f(5) 5g(5)

Mathematics

1 answer:

Alexxandr [17]2 years ago

5 0

Answer:

they F (5) g (5)

Step-by-step explanation:

(fg)=(f.g)

and then this is the first doing (fg)(X)= f(x) [g(x)]

x=5

f(5).g(X)

and they final result is

they top of answer

happy answering

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Answer:

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2 years ago

Four times a first number decreased by a second number is - 14. The first

mel-nik [20]

Answer:

f = -5, s = -6

Step-by-step explanation:

F= first number

S= second number

4f - s = -14

f + 3s = -23

3(4f - s = -14)

12f - 3s = -42

+ f + 3s = -23

13f = -65

————

f = -5

4f - s = -14

4(-5) - s = -14

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+20 +20

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———

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2 years ago

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Answer:

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Step-by-step explanation:

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2 years ago

Which polynomial function has a leading coefficient of 1 and roots 21 and 31 with multiplicity 1?

schepotkina [342]

Answer:

Which i think is the first one, there may just be a typing error.

Step-by-step explanation:

A polynomial of order n has the following format:

$f(x) = a(x - x_{0})(x - x_{1})...(x - x_{n-1})$

In which a is the leading coefficient, $x_{0}, x_{1},..., x_{n-1}$ are the roots.

If a root appears m times, they are said to have multiplicity m.

Leading coefficient of 1 and roots 21 and 31 with multiplicity 1

$f(x) = 1(x - 21)(x - 31)$

So the correct answer is:

$f(x) = 1(x - 21)(x - 31)$

Which i think is the first one, there may just be a typing error.

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2 years ago

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aliya0001 [1]

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2 years ago