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2 years ago

What is the area of the above trapezoid? Please help I will cash app if you help out

Mathematics

1 answer:

Leno4ka [110]2 years ago

7 0

Answer:

b should be correct

Step-by-step explanation:

no need to cash app me its been a while since ive done math so i dont even know if this is right

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A positive integer is twice another.the sum of the reciprocal of the two positive integer is 3/14. Find the integers

icang [17]

Answer:

$\huge\boxed{14\ \text{and}\ 7}$

Step-by-step explanation:

$n,\ m-\text{positive integer}\\\\n=2m-\text{a positive integer is twice another}\\\\\dfrac{1}{n}+\dfrac{1}{m}=\dfrac{3}{14}-\text{the sum of the reciprocal of the two positive integer is }\ \dfrac{3}{14}\\\\\text{We have the system of equations:}\\\\\left\{\begin{array}{ccc}n=2m&(1)\\\dfrac{1}{n}+\dfrac{1}{m}=\dfrac{3}{14}&(2)\end{array}\right$

$\text{Substitute (1) to (2):}\\\\\dfrac{1}{2m}+\dfrac{1}{m}=\dfrac{3}{14}\\\\\dfrac{1}{2m}+\dfrac{1\cdot2}{m\cdot2}=\dfrac{3}{14}\\\\\dfrac{1}{2m}+\dfrac{2}{2m}=\dfrac{3}{14}\\\\\dfrac{1+2}{2m}=\dfrac{3}{14}\\\\\dfrac{3}{2m}=\dfrac{3}{14}\Rightarrow2m=14\qquad\text{divide both sides by 2}\\\\\dfrac{2m}{2}=\dfrac{14}{2}\\\\\boxed{m=7}$

$\text{Substitute it to (1):}\\\\n=2\cdot7\\\\\boxed{n=14}$

8 0

2 years ago

The operator of a pumping station has observed that demand for water during early afternoon hours has an approximately exponenti

melomori [17]

Answer:

a) 0.1496 = 14.96% probability that the demand will exceed 190 cfs during the early afternoon on a randomly selected day.

b) Capacity of 252.6 cubic feet per second

Step-by-step explanation:

Exponential distribution:

The exponential probability distribution, with mean m, is described by the following equation:

$f(x) = \mu e^{-\mu x}$

In which $\mu = \frac{1}{m}$ is the decay parameter.

The probability that x is lower or equal to a is given by:

$P(X \leq x) = \int\limits^a_0 {f(x)} \, dx$

Which has the following solution:

$P(X \leq x) = 1 - e^{-\mu x}$

The probability of finding a value higher than x is:

$P(X > x) = 1 - P(X \leq x) = 1 - (1 - e^{-\mu x}) = e^{-\mu x}$

The operator of a pumping station has observed that demand for water during early afternoon hours has an approximately exponential distribution with mean 100 cfs (cubic feet per second).

This means that $m = 100, \mu = \frac{1}{100} = 0.01$

(a) Find the probability that the demand will exceed 190 cfs during the early afternoon on a randomly selected day. (Round your answer to four decimal places.)

We have that:

$P(X > x) = e^{-\mu x}$

This is P(X > 190). So

$P(X > 190) = e^{-0.01*190} = 0.1496$

0.1496 = 14.96% probability that the demand will exceed 190 cfs during the early afternoon on a randomly selected day.

(b) What water-pumping capacity, in cubic feet per second, should the station maintain during early afternoons so that the probability that demand will exceed capacity on a randomly selected day is only 0.08?

This is x for which:

$P(X > x) = 0.08$

$e^{-0.01x} = 0.08$

$\ln{e^{-0.01x}} = \ln{0.08}$

$-0.01x = \ln{0.08}$

$x = -\frac{\ln{0.08}}{0.01}$

$x = 252.6$

Capacity of 252.6 cubic feet per second

5 0

2 years ago

Find the area of the shaded region.

MariettaO [177]

Answer:

Area of shaded region = 134.13 square feet

Step-by-step explanation:

Area of the shaded region = Area of square - Area of circle

$= ( 25 \times 25) - ( \pi 12.5^2)\\= 625 - 490.87\\= 134.13 ft^2$

8 0

2 years ago

solve image :) What is the equation of the line that has a slope of 3 and passes through the point (-4, 1)?

Lesechka [4]

Answer:

Step-by-step explanation:

The point slope form of a line is

y - y1 = m(x - x1) where m = the slope, and (x1, y1) is a point on the line.

So, substituting:

y - 1 = 3(x - -4)

y - 1 = 3(x + 4)

y = 3x + 12 + 1

y = 3x + 13.

6 0

2 years ago

A pine cone drops from a tree branch that is 36 feet above the ground. The function h = –16t2 + 36 is used. If the height h of t

scoray [572]

Notice that the height of the pine cone when it hits the ground is zero. So, to find the tame it takes for the pine cone to hit the ground, we just need to replace the height, $h$ , with 0 in the function, and solve for time $t$ :
$h=-16t^2+36$
$0=-16t^2+36$
$-36=-16t^2$
$t^2= \frac{-36}{-16}$
$t^2= \frac{9}{4}$
$t=(+/-) \sqrt{ \frac{9}{4} }$
$t=(+/-) \frac{3}{2}$
$t=(+/-)1.5$
Since time cannot be negative, the solution is $t=1.5$ seconds.

Since 1.5 second is significantly less than 2 seconds, we can conclude that <span>2 seconds is not a reasonable answer to this model.</span>

6 0

3 years ago

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