Answer:
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Step-by-step explanation:
I can help you understand this, however there is nothing but 'M'
Answer:
The answer is C. y=2x+3
Step-by-step explanation:
A. y=3x you would pick a coordinate to replace the X and Y value. -1=3(-2) which gives you -1=-6, which wouldn't work.
B. y=x+1 you would pick a coordinate to replace the X and Y value. -1=-2+1 which would give you -1=-1 which would work, but you have to check all of the coordinates to make sure it is the correct one. 3=0+1 which would give you 3=1 so this is not the correct answer.
C. y=2x+3 You would pick a coordinate to replace the X and Y value. -1=2(-2)+3 so then you would simplify that which would give you -1=-1 which would work, but you still need to check to make sure that all of the coordinates work. 3=2(0)+3 which would give you 3=3. 9=2(3)+3 which would give you 9=9. Since this one is able to have three coordinates that can be plugged into it more than likely it is the correct answer, but just to be certain lets see if D will work.
D. y=x+13 you would substitute the coordinates for the x and y values -1=-2+13 which would give you -1=11 which would not be correct.
Answer:
= A(t) = 120000(1.06)^t t = 1 year
We just add ^12 to equal 1/12 months.
Then use the notation below.
Step-by-step explanation:
We simply want to write an equivalent form of the same equation that will allow for the time period to be calculated in years.
For one year, t = 1, we want it to grow 6% = 1.06
Yearly Rate of Growth annual equation: = 7200
P(i) 7200/ 120000 x 100% = 6% per year growth rate
the yearly growth factor is 1 + appreciation rate = 1+i =1+0.06= 1.06
So time in years can be added to t
= A(t) = 120000(1.06)^t t = 1 year
The yearly growth factor = 1.06
To equate monthly we add the exponent t*12*1/12 before 120000(1.06)^t
then add 1/12 to replace ^t = monthly, or just keep the t= time
A(t) = 120000(1.06)^12t
Answer: Discriminant.
Step-by-step explanation:
1. The quadratic formula is:
2. And the discriminant is inside the square root:
2. Then, if the discriminant is negative, the quadratic equation does not have real solutions, it has two imaginary solutions. If the discriminant is zero the quadratic has one solution. If the discriminant is positive, the quadratic equation has two distinct solutions.
