Question

Evaluate the expression for x = 2 and y = 4. Enter your answer in the box. 16x0 + 2x2 • y –1

Answer 1

Given that,

The given expression is : $16x^0+2x^2{\cdot}y^{-1}$

To find,

The value of the above expression when x = 2 and y = 4

Solution,

We have,

$16x^0+2x^2{\cdot}y^{-1}$

Put x = 2 and y = 4 in the above expression.

$16x^0+2x^2{\cdot}y^{-1}\\\\=16\times (2)^0+2(2)^2\times (4)^{-1}\\\\=16\times 1+2(2)^2\times\dfrac{1}{4}\\\\=16+2\\\\=18$

So, the value of the above expression is 18.