Which function corresponds to the table? x y 0 3 1 1 2 -1

C U12122 Write a Sum or Difference as a Product A 8 Questions 1. Use the GCF to rewrite the sum as a product. 30 + 16 a) 8 (3+2)

Alex73 [517]

Answer:

2(15+8)

Step-by-step explanation:

Given the expression 30+16

We are to use GCF to rewrite the sum as a product.

Get the factor of each value first as shown;

30 = 2 * 15

16 = 2 * 8

substitute the factors back into the expression:

30+16 = (2*15)+(2*8)

Since 2 is common to both terms, then:

30+16 = 2(15+8)

Hence the required sum of product of the terms is 2(15+8)

8 0

2 years ago

Solve each of the following quadratic equations 3x=0.5x^2 0=5x^2-2x+6

UNO [17]

Question 1

$3x=0.5x^{2}\\\\6x=x^{2} \\ \\ x^{2}-6x=0 \\ \\ x(x-6)=0 \\ \\ \boxed{x=0, 6}$

Question 2

$0=5x^{2}-2x+6 \\ \\ x=\frac{2 \pm \sqrt{(-2)^{2}-4(5)(6)}}{2} \\ \\ x=\frac{2 \pm \sqrt{-116}}{10} \\ \\ x=\frac{2 \pm 2i\sqrt{29}}{10} \\ \\ \boxed{x=\frac{1 \pm i\sqrt{29}}{5}}$

6 0

2 years ago

At the movie theatre, child admission is $5.10 and adult admission is $9.00 .

sveticcg [70]

Answer:

$5.10 X +9.00 Y = 831.60$

We also know that for Wedneday we have two times tickets for adults compared to child so we have

$Y =2x$

And using this condition we have:

$5.10 X + 18 X = 831.60$

And solving for X we got:

$X= \frac{831.60}{23.1}=36$

So then the number of tickets sold for child are 36

Step-by-step explanation:

For this problem we can set upt the following notation

X = number of tickets for child

Y= number of tickets for adults

And we know that the total revenue for Wednesday was 831.60. So then we can set up the following equation for the total revenue

$5.10 X +9.00 Y = 831.60$

We also know that for Wedneday we have two times tickets for adults compared to child so we have

$Y =2x$

And using this condition we have:

$5.10 X + 18 X = 831.60$

And solving for X we got:

$X= \frac{831.60}{23.1}=36$

So then the number of tickets sold for child are 36

8 0

3 years ago

CAN SOMEONE PLEASE HELP ME WITH NUMBER 2

lyudmila [28]

Answer:

Step-by-step explanation:

It's B.

So the equation is x > -25. In word form, "The solution to this equation is greater than -25."

B begins at -25, and has a thick arrow pointing in the positive direction.

5 0

3 years ago

A map uses a scale of 3/4 in = 80 miles. If two buildings are 60 miles apart in real life, how far apart would they be drawn on

Alla [95]

Given:

The scale of a map is $\dfrac{3}{4}\ in=80\ miles$ .

The distance between two buildings is 60 miles.

To find:

The distance between the given building on the map.

Solution:

We have,

$\dfrac{3}{4}\ in=80\ miles$

It means, 80 miles in real life = $\dfrac{3}{4}\ in$ on the map.

1 mile in real life = $\dfrac{3}{4\times 80}\ in$ on the map.

60 mile in real life = $\dfrac{3\times 60}{4\times 80}\ in$ on the map.

= $\dfrac{180}{320}\ in$ on the map.

= $\dfrac{9}{16}\ in$ on the map.

Therefore, the buildings are $\dfrac{9}{16}\ in$ apart on the map.

7 0

2 years ago