Answer:
Step-by-step explanation:
Please, share the answer options next time.
1) f(x) = 2x^2– x – 6 is a quadratic function.
2) The coefficients of this polynomial are a = 2, b = -1 and c = -6
2) Its graph opens up.
3) The x-value of the axis of symmetry and the vertex is x = -b / (2a), which here comes out to x = -(-1) / [2(2)], or x = 1/4
4) the y coordinate of the vertex is f(1/4), or -6 1/8
5) The vertex is at (1/4, -6 1/8)
6) The y-intercept is at f(0): 2(0)^2 - 0 - 6 = -6 => (0, -6)
For this problem, we use the repeated trials equation:
P = n!/r!(n-r)!*p^(n-r)*q^r
where
P is the total probability of having r successful trials out of the total n trials. p is equal to 13/58, while q is equal to 1 - 13/58.
P = 4!/4!(4-4)!*(13/58)^(4-4)*(1 - 13/58)^4
P = 0.362 or 36.2%
2 n - 5 = 3
So A is the answer
