The most important security consideration for the station is code signing. With code signing, consumers may feel confident about the software they are downloading and can stop worrying about infecting their computer.
With code signing, consumers may feel confident about the software they are downloading and can stop worrying about infecting their computer or mobile device with malware. Code signing has grown in importance for software developers and distributors as more software may be downloaded from the Internet.
Malware can be easily installed on a victim's computer by an attacker who poses as a trustworthy source. As long as users only download software that is regarded as safe by their operating system, code signing ensures that these types of assaults cannot happen.
Nowadays, the Operating System looks for the digital certificate produced through code signing when software is downloaded onto a computer to ensure the security of the software being installed. The user is informed and given the option to stop or continue the installation if no digital certificate is detected.
To know more about code signing click here:
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That would be called a <span>tachometer </span>
Answer:
Windows 10 if this is what I think u mean
Answer: 10 students
Explanation:
Students younger than 10 = 50%
Students that are 10years old = 1/20 = 1/20 × 100 = 5%
Students that are older than 10 but younger than 12 = 1/10= 1/10 × 100 = 10%
Students that are 12 years or older
= 100% - (50% + 5% + 10%)
= 100% - 65%
= 35%
This means that 35% of the students are 12 years or older and we've been given the number as 70.
Let's say the total number of students is x. Therefore,
35% of x = 70
0.35 × x = 70
0.35x = 70
x = 70/0.35
x = 200
The total number of students is 200.
Therefore, the number of students that are 10years will be:
= 1/20 × 200
= 10 students
Therefore, 10 students are 10 years.
Answer
First part:
The transmitted 8-bit sequence for ASCII character '&' with odd parity will be 00100110. Here leftmost bit is odd parity bit.
Second part:
The invalid bit sequence are option a. 01001000 and d. 11100111
Explanation:
Explanation for first part:
In odd parity, check bit of either 0 or 1 is added to the binary number as leftmost bit for making the number of 1s in binary number odd.
If there are even number of 1s present in the original number then 1 is added as leftmost bit to make total number of 1s odd.
If there are odd number of 1s present in the original number then 0 is added as leftmost bit to keep the total number of 1s odd.
Explanation for second part:
A valid odd parity bit sequence will always have odd number of 1s.
Since in option a and d, total number of 1s are 2 and 6 i.e. even number. Therefore they are invalid odd parity check bit sequences.
And since in option b and c, total number of 1s are 5 and 7 i.e. odd numbers respectively. Therefore they are valid odd parity check bit sequences.
