Plz help, i give brainliest

you are a school photographer taking individual and class pictures for 2 classes of 21 students each on average each individual

uysha [10]

Answer: Approximately 146 minutes (or if you need the simplified version the answer is 2 hours and 26 minutes). Step-by-step explanation: Step 1. Two classes of 21 students. To calculate that you would multiply 21 by 2. 21*2=42 Step 2. So now we know you need 42 individual pictures. If they each take 3 minutes to take you need to multiply 42 by 3. 42*3=126. So now you know it’ll take 126 minutes to take all the individual pictures. Step 3. Now, there are 2 classes of people and it takes 10 minutes to take each class picture. So do calculate that you need to multiply 10 by 2. 10*2=20. So it’ll take 20 minutes to take both class pictures. Step 4. Now we know it’ll take 126 minutes to take all the individual photos and 20 minutes to take the class photos. Now to calculate the total amount of time it’ll take to take all the photos you need to add 20 to 126. 126+20=146. So, it’ll take 146 minutes to take all the photos. Step 5. (You can skip this step if no simplification is needed in your problem) So, we all know there is 60 minutes in an hour so we’ll divide 146 by 60. 146/60=2.43. So, now we know it’ll take 2.43 hours to take all the photos. 2.43 hours is 2 hours and 26 minutes. I hope this helps!

4 0

3 years ago

Simplify the expression by combining like terms.

ollegr [7]

Answer:

Hi... Your answer is

-22d+f

4 0

3 years ago

Read 2 more answers

<img src="https://tex.z-dn.net/?f=%5C%7B%20%5Cfrac%20%7B%20%28%20%5Csqrt%20%7B%203%20%7D%20%29%20%5Ctimes%203%20%5E%20%7B%20-%20

ZanzabumX [31]

Answer:

Step-by-step explanation:

Exponent law:

$\sf \bf a^m * a^n = a^{m+n}\\\\ (a^m)^n = a^{m*n}$

$\sf a^{-m}=\dfrac{1}{a^m}$

First convert radical form to exponent form and then apply exponent law.

$\sf \sqrt{3}=3^{\frac{1}{2}}\\\\\sqrt{5}=5^{\frac{1}{2}}$

$\sf \left(\dfrac{(\sqrt{3}*3^{-2}}{(\sqrt{5})^2}\right)^{\frac{1}{2}}= \left(\dfrac{3^{\frac{1}{2}}*3^{-2}}{(5^{\frac{1}{2}})^2} \right )^{\frac{1}{2}}$

$= \left(\dfrac{3^{\frac{1}{2}-2}}{5^{\frac{1}{2}*2}}\right)^{\frac{1}{2}}\\\\=\left(\dfrac{3^{\frac{1-4}{2}}}{5}\right)^{\frac{1}{2}}\\\\=\left(\dfrac{3^{\frac{-3}{2}}}{5}\right)^{\frac{1}{2}}\\\\=\dfrac{3^{\frac{-3}{2}*{\frac{1}{2}}}}{5^{\frac{1}{2}}}\\\\ =\dfrac{3^{{\frac{-3}{4}}}}{5^{\frac{1}{2}}}$

3 0

2 years ago

Solve for x. A. 19 B. 17 C. 15 D. 11

Crazy boy [7]

Answer:

B. 17

Step-by-step explanation:

By the property of intersecting secants outside of a circle, we have:

7 (7 + x) = 8 (13 + 8)

49 +7x = 8*21

7x = 168 - 49

7x = 119

x = 119/7

x = 17

5 0

3 years ago

Order from least to greatest: 1/8, 0.78, 15%, 1/20

Mrrafil [7]

Answer:

1/20, 1/8, 15%, 0.78

Step-by-step explanation:

Order from least to greatest: 1/8, 0.78, 15%, 1/20

1)Convert all into decimals to make it easier, this can be done with a simple look up of a conversion calculator!

1/8 = .125

15% = .15

1/20 = .05

0.78 = 0.78 (duh)

Then simply put them in order. Hope this was clear!

5 0

4 years ago