Answer:
<h3>lt = lo/cos²θ</h3>
Step-by-step explanation:
Given the intensity of the transmitted light It and θ are related by the equation Cosθ= √ Io/It, we are to write lt as a function of lo
Given the equation
Cosθ= √ Io/It
Let us make lt the subject of the formula;
square both sides of the equation
(Cosθ)²= (√ Io/It)²
cos²θ = lo/lt
cross multiply
ltcos²θ = lo
divide both sides by cos²θ
ltcos²θ/ cos²θ= lo/cos²θ
lt = lo/cos²θ
Hence the expression of lt as a function of lo is lt = lo/cos²θ
First let's review how to expand this!
(ax+b)^2=a^2*x^2+2abx+a^2
In this case
(2x^2+1/2)^2=2^2*x^2+2*1/2*2x+(1/2)^2
=4x^2+2x+1/4
Done!
Podrias explicar lo que estas tratando de buscar? tu pregunta no se entiende
Answer:
0.16
Step-by-step explanation:
I took the test
Answer:
-w²+49x²-8wx
Step-by-step explanation:
if you want how I did this it's quite lengthy so let me know if you want the process
