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pickupchik [31]
3 years ago
10

What's the best quote your heard of?

Mathematics
1 answer:
Mars2501 [29]3 years ago
8 0

Step-by-step explanation:

꧁§༺⚔A real friend is one who walks in when the rest of the world walks out.” ⚔༻§꧂

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Identify the terms, like terms, coefficients, and constants in each expression.
steposvetlana [31]
Simplifying
8 + 6t = 3t + t

Combine like terms: 3t + t = 4t
8 + 6t = 4t

Solving
8 + 6t = 4t

Solving for variable 't'.

Move all terms containing t to the left, all other terms to the right.

Add '-4t' to each side of the equation.
8 + 6t + -4t = 4t + -4t

Combine like terms: 6t + -4t = 2t
8 + 2t = 4t + -4t

Combine like terms: 4t + -4t = 0
8 + 2t = 0

Add '-8' to each side of the equation.
8 + -8 + 2t = 0 + -8

Combine like terms: 8 + -8 = 0
0 + 2t = 0 + -8
2t = 0 + -8

Combine like terms: 0 + -8 = -8
2t = -8

Divide each side by '2'.
t = -4

Simplifying
t = -4
8 0
3 years ago
Pls help it is due today
tino4ka555 [31]

Answer:

25 salads

Step-by-step explanation:

20% is 1/5 of the circle. there were 5 salads sold in that category. 5x5=25.

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Randomization in an experiment is important because it ensures that
Alexeev081 [22]

Answer:

C.) each treatment is thought of as a value of the explanatory variable

Step-by-step explanation:

The main purpose for using randomization in an experiment is to control the lurking variable and establish a cause and effect relationship.

If we do not control lurking, or confounding, variables, we cannot accurately establish a cause and effect relationship; this means we cannot ensure that each treatment is a value of the explanatory variable.

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Answer:

14.387

Step-by-step explanation:

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3 years ago
raph the equation with a diameter that has endpoints at (-3, 4) and (5, -2). Label the center and at least four points on the ci
andreyandreev [35.5K]

Answer:

Equation:

{x}^{2}   +  {y}^{2} +  2x  - 2y   -  35= 0

The point (0,-5), (0,7), (5,0) and (-7,0)also lie on this circle.

Step-by-step explanation:

We want to find the equation of a circle with a diamterhat hs endpoints at (-3, 4) and (5, -2).

The center of this circle is the midpoint of (-3, 4) and (5, -2).

We use the midpoint formula:

( \frac{x_1+x_2}{2}, \frac{y_1+y_2,}{2} )

Plug in the points to get:

( \frac{ - 3+5}{2}, \frac{ - 2+4}{2} )

( \frac{ -2}{2}, \frac{ 2}{2} )

(  - 1, 1)

We find the radius of the circle using the center (-1,1) and the point (5,-2) on the circle using the distance formula:

r =  \sqrt{ {(x_2-x_1)}^{2} + {(y_2-y_1)}^{2} }

r =  \sqrt{ {(5 -  - 1)}^{2} + {( - 2- - 1)}^{2} }

r =  \sqrt{ {(6)}^{2} + {( - 1)}^{2} }

r =  \sqrt{ 36+ 1 }  =  \sqrt{37}

The equation of the circle is given by:

(x-h)^2 + (y-k)^2 =  {r}^{2}

Where (h,k)=(-1,1) and r=√37 is the radius

We plug in the values to get:

(x- - 1)^2 + (y-1)^2 =  {( \sqrt{37}) }^{2}

(x + 1)^2 + (y - 1)^2 = 37

We expand to get:

{x}^{2}  + 2x  + 1 +  {y}^{2}  - 2y + 1 = 37

{x}^{2}   +  {y}^{2} +  2x  - 2y +2 - 37= 0

{x}^{2}   +  {y}^{2} +  2x  - 2y   -  35= 0

We want to find at least four points on this circle.

We can choose any point for x and solve for y or vice-versa

When y=0,

{x}^{2}   +  {0}^{2} +  2x  - 2(0)  -   35= 0

{x}^{2}   +2x   -   35= 0

(x - 5)(x + 7) = 0

x = 5 \: or \: x =  - 7

The point (5,0) and (-7,0) lies on the circle.

When x=0

{0}^{2}   +  {y}^{2} +  2(0)  - 2y   -  35= 0

{y}^{2} - 2y   -  35= 0

(y - 7)(y + 5) = 0

y = 7 \: or \: y =  - 5

The point (0,-5) and (0,7) lie on this circle.

3 0
3 years ago
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