9514 1404 393
Answer:
59) not similar
60)
Step-by-step explanation:
59) The ratios of the side lengths shown cannot be reduced. They are different, so the triangles are not similar.
7:8:12 ≠ 6:7:11
__
60) The side length ratios both reduce to 8:7:10, so the triangles are similar.
∆ABC ~ ∆JKL
The scale factor is LJ/CA = 25/20 = 5/4. (Multiplying ABC by 5/4 will give JKL.)
The answer is: <span>16.82
it's tan (angle)=opposite/adjacent</span>
The answer is the first one
Given:
There exist a proportional relationship between x and y.
To find:
The equation which represents a proportional relationship between x and y.
Solution:
If there exist a proportional relationship between x and y, then


where, k is constant of proportionality.
We know that, proportional relationship passes through the origin because (0,0) satisfy
.
For x=0, check which equation has y=0.
In option A,
.
In option B,
.
In option C,
.
In option D, 
Only in option C, we have a equation of the form
with 4 as constant of proportionality and it passes through (0,0).
Therefore, the correct option is C.
If you do in fact mean
(as opposed to one of these being the derivative of
at some point), then integrating twice gives



From the initial conditions, we find


Eliminating
, we get


![C_1 = -\dfrac{\ln(6)}5 = -\ln\left(\sqrt[5]{6}\right) \implies C_2 = \ln\left(\sqrt[5]{6}\right)](https://tex.z-dn.net/?f=C_1%20%3D%20-%5Cdfrac%7B%5Cln%286%29%7D5%20%3D%20-%5Cln%5Cleft%28%5Csqrt%5B5%5D%7B6%7D%5Cright%29%20%5Cimplies%20C_2%20%3D%20%5Cln%5Cleft%28%5Csqrt%5B5%5D%7B6%7D%5Cright%29)
Then
![\boxed{f(x) = \ln|x| - \ln\left(\sqrt[5]{6}\right)\,x + \ln\left(\sqrt[5]{6}\right)}](https://tex.z-dn.net/?f=%5Cboxed%7Bf%28x%29%20%3D%20%5Cln%7Cx%7C%20-%20%5Cln%5Cleft%28%5Csqrt%5B5%5D%7B6%7D%5Cright%29%5C%2Cx%20%2B%20%5Cln%5Cleft%28%5Csqrt%5B5%5D%7B6%7D%5Cright%29%7D)