Step-by-step answer:
Given:
mean, mu = 200 m
standard deviation, sigma = 30 m
sample size, N = 5
Maximum deviation for no damage, D = 100 m
Solution:
Z-score for maximum deviation
= (D-mu)/sigma
= (100-200)/30
= -10/3
From normal distribution tables, the probability of right tail with
Z= - 10/3
is 0.9995709, which represents the probability that the parachute will open at 100m or more.
Thus, by the multiplication rule, the probability that all five parachutes will ALL open at 100m or more is the product of the individual probabilities, i.e.
P(all five safe) = 0.9995709^5 = 0.9978565
So there is an approximately 1-0.9978565 = 0.214% probability that at least one of the five parachutes will open below 100m
Answer:
The answer is B) 152
Step-by-step explanation:
ABF= 28 degrees
BCD= 28 degrees since vertical angle are congruent
ABC= 180 -28 = 152 degrees
the answer is 2x2+12z-5 (its also in the picture)
Answer:
P = 7
Step-by-step explanation:
We have 21 total cards and out of those 21 cards, 14 of those are birthday cards. So that means that the amount of cards that are not birthday cards is the number of cards subtracted by the number of birthday cards, also shown as 21 - 14. So 21 - 14 = P, so now we solve what 21 - 14 is which is 7, so that means P = 7.
Let me know if you have any questions.