First, we find the time spent accelerating:
s = ut + 1/2 at²; u = 0
10 = 1/2 5t²
t = 2 seconds
Velocity at point B:
v = u + at; u = 0, a = 5 m/s², t = 2 s
v = (5)(2) = 10 m/s
Now, the same velocity is at C so we find the time decelerating to 0 in CD
v = u + at, v = 0, u = 10 m/s, a = -4 m/s²
0 = 10 - 4t
t = 2.5 seconds
Total time = time(AB) + time(BC) + time(CD)
20 = 2 + time(BC) + 2.5
time(BC) = 15.5 seconds
Distance = velocity x time
BC = 10 x 15.5
= 155 m
Answer:
Step-by-step explanation:
Given
× 
Cancel the factor (a - 3) on the numerator and denominator
Cancel the 5 and 15 by dividing both by 5, leaving
Since 5/3 is an inproper fraction it then becomes 1 2/3 and if you put both of the fractions into a common denominator you get 1 16/24>15/24
Please give me a thanks if you feels it is the right answer
Answer:
The last option = 1.37 × 10 race to -5
The answer is on the table.
3:24 and 5:40 are all equal to 1:8
