Answer:
I assume you mean 16^(1/3) i.e. the cube root of 16
I am also assuming you mean the real cube root because, as you may know, every non-zero real number has three cube root - one real and two complex conjugates.
Since 16 = 8 x 2 and 8 = 2³ then (2³ x 2)^1/3 = (2³)^1/3 x 2^1/3 = 2 x 2^1/3
You might check that the cube root of 16 is about 2.52 which is twice the cube root of 2
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x-x-y
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<h2>x = -5</h2><h2>y = -2</h2>
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Answer:
umm scuze nu stiu raspunsul insa chiar vreau punctele imi poti da alta intrebare mai usoara pls?
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