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ryzh [129]
3 years ago
14

I need help... on this question.

Mathematics
2 answers:
KATRIN_1 [288]3 years ago
8 0

Answer:

Step-by-step explanation:

A+B= we will add both expressions

A+B=3x^4+2x^2-2x+1-2x^3+4x^2-3  we will add like terms

A+B= 3x^4-2x^3+6x^2-2x-2

A-B=3x^4+2x^2-2x+1-(-2x^3+4x^2-3)

A-B=3x^4+2x^2-2x+1+2x^3-4x^2+3

A-B=3x^4+2x^3-2x^2-2x+4

Kobotan [32]3 years ago
3 0
If I help can you help me with my question?
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SOMEONE PLZZZ HELP THIS IS DUE IN 2 MINSSS
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Answer:

D, and C sorry if I'm wrong

5 0
3 years ago
At the book store, you purchased some $3 clearance mystery books and $8
nasty-shy [4]

Answer:

15 of $3 books and 4 of the $8 books

Step-by-step explanation:

15×3= 45

8 × 4= 34

45+32= 77

3 0
3 years ago
Can anyone help? I’d greatly appreciate it :)
Lena [83]

Answer:

bilmiyorum sna kolu gelsın

8 0
3 years ago
Stan's cookie recipe makes 24 cookies and calls for exactly 384 sprinkles. He is wondering how many sprinkles (p ) he will need
Arisa [49]

Answer:

960

Step-by-step explanation:

<u>Given:</u>

  • Stan's cookie recipe makes 24 cookies.
  • It needs exactly 384 sprinkles.

<u>To Find:</u>

  • Number of sprinkles needed for 60 cookies
<h2><u>Solution:</u></h2>

<u>Find the number of sprinkles needed for 1 cookie:</u>

  • 24 cookies = 384 sprinkles
  • 1 cookie = 384 ÷ 24
  • 1 cookie = 16 sprinkles

<u>Find the number of sprinkles needed for 60 cookies:</u>

  • 1 cookie = 16 sprinkles
  • 60 cookies = 16 x 60
  • 60 cookies = 960 sprinkles

Answer:  Stan will need 960 sprinkles for 60 cookies.

3 0
2 years ago
A grower believes that one in five of his citrus trees are infected with the citrus red mite. How large a sample should be taken
mihalych1998 [28]

Answer:

n=6147

Step-by-step explanation:

1) Notation and definitions

X=1 number of citrus trees that are infected with the citrus red mite.

n=5 random sample taken

\hat p=\frac{1}{5}=0.2 estimated proportion of citrus trees that are infected with the citrus red mite.

p true population proportion of citrus trees that are infected with the citrus red mite.

Me=0.01 represent the margin of error desired

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".  

The margin of error is the range of values below and above the sample statistic in a confidence interval.  

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  

The population proportion have the following distribution

p \sim N(p,\sqrt{\frac{\hat p(1-\hat p)}{n}})

In order to find the critical values we need to take in count that we are finding the interval for a proportion, so on this case we need to use the z distribution. Since our interval is at 95% of confidence, our significance level would be given by \alpha=1-0.95=0.05 and \alpha/2 =0.025. And the critical values would be given by:

t_{\alpha/2}=-1.96, t_{1-\alpha/2}=1.96

The margin of error for the proportion interval is given by this formula:  

ME=z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}    (a)  

And on this case we have that ME =\pm 0.01 and we are interested in order to find the value of n, if we solve n from equation (a) we got:  

n=\frac{\hat p (1-\hat p)}{(\frac{ME}{z})^2}   (b)  

And replacing into equation (b) the values from part a we got:

n=\frac{0.2(1-0.2)}{(\frac{0.01}{1.96})^2}=6146.56  

And rounded up we have that n=6147

5 0
4 years ago
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