Answer:
4n^3-n^2-5n
Step-by-step explanation:
n(2n+4n2−5−3n)
=(n)(2n+4n2+−5+−3n)
=(n)(2n)+(n)(4n2)+(n)(−5)+(n)(−3n)
=2n2+4n3−5n−3n2
=4n3−n2−5n
A kilogram is 1000 grams. Therefore, 5000 g is 5 kg
Weird way to write it but alright! (Sideways)
19pq^-2 x 5pq^6 = ?
These problems are pretty much single operations between each of the variables / constants.
So it's like this:
(19*5)(p*p)(q^-2*q^6) = ?
19*5 is 95.
For p*p remember that when two variables multiply there given powers add. In the case where the powers are not shown (like in the case of p*p) they are always assumed to be 1. So what is 1+1? 2.
p*p is p^2
For q^-2*q^6 it is the same deal with the previous problem. So now the problem looks like this:
-2 + 6 = 4
(The two is negative, because the power is negative 2)
So, q^4.
Our final answer is all of the combined.... like a so:
95p^2q^4
Equation:
y + 2 = 1/3(x+1)
Assuming you are solving for Y:
y + 2 = 1/3(x) + 1/3(1)
(y + 2) - 2 = (1/3x + 1/3) - 2
y = 1/3x + 1/3 - 2
<u>y = 1/3x - 5/3</u>
