Answer:
a) 2nd
b) 4.8
c) 4
Step-by-step explanation:
Mode is the highest frequency.
"Away" has highest frequency in the second quarter
Mean = sum/n
Sum of Home goals:
5+4+8+9 = 26
Sum of Away goals:
2+9+7+4 = 22
Total goals = 26+22 = 48
Average = 48/10 = 4.8
No. of home goals - No. of away goals
26 - 22 = 4
Answer:
(20.) D is the correct answer
(19.) A is correct
(18.) A is correct
(17.) D is correct
(15.) A is correct
Step-by-step explanation:
hope this helps u ;)
If there are 10 dogs in each room there are 40 dogs
Answer:
Step-by-step explanation:
Given that
Group Group One Group Two
Mean 26.00 23.00
SD 2.00 4.00
SEM 0.40 1.21
N 25 11
where group I represents female servers and group II male servers.
We have to calculate confidence interval for 90% for difference in means
The mean of Group One minus Group Two equals 3.00
df = 34
standard error of difference = 0.993
t critical = 2.034 for 90% df 34
Hence confid. interval at 90%
=Mean diff ±2.034 * std error of diff
= (0.98, 5.02)
Answer:
13800
Step-by-step explanation:
The order of the members is important (because each selected member will receive a different position), thus we then need to use the definition of permutation.
There are 25 members, of which 3 are selected.

Evaluate the definition of a combination:
