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2 years ago

Use the Triangle Inequality Property to determine whether a triangle can be formed with the given side lengths. 4 m, 8 m, 9 m *

Mathematics

1 answer:

Illusion [34]2 years ago

7 0

Answer:

Therefore a triangle can be formed with side lengths of 4 m, 8 m, 9 m

Step-by-step explanation:

A triangle is a polygon with three sides and three angles. There are different types of triangles such as scalene, isosceles, equilateral and so on.

The triangle inequality property states that the sum of any two sides of a triangle must be greater than the third side. If a, b and c are the sides of a triangle then:

a + b > c; a + c > b; b + c > a

Given a triangle with side length 4 m, 8 m, 9 m:

4m + 8m = 12m > 9m

4m + 9m = 13m > 8m

8m + 9m = 17m > 4m

Therefore a triangle can be formed with side lengths of 4 m, 8 m, 9 m.

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creativ13 [48]

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Step-by-step explanation:

Being king gets passed down, and so does being an aristocrat.

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2 years ago

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Find the length of the hypotenuse to the nearest tenth. (example 4.5)<br> 7<br> 2<br>

Vsevolod [243]

Answer:

hypotenuse = 7.3

Step-by-step explanation:

the length two legs of the given triangle are 7 and 2 respectively.

using pythagoras theorem

a^2 + b^2 = c^2

7^2 + 2^2 = c^2

49 + 4 = c^2

53 = c^2

$\sqrt{53}$ = c

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2 years ago

A grocer wants to mix nuts costing 5.00 per kilogram with nuts costing 8.00 per kilogram to make a 10 kilogram mixture for 6.00

vladimir1956 [14]

Step-by-step explanation:

let E be weight of expensive nuts, C be cheaper nuts

E*8+C*5=10*6 value equation

E+C=10 mass equation

Solve it by any method, I will do determinants

Det: 8-5=3

E= (60-50)/3=10/3 =3.33 lb

C= 80-60 /3=20/3 =6.66 lb

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1 year ago

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A normal distribution has a mean of 137 and a standard deviation of 7. Find the z-score for a data value of 121. Incorrect Round

Neko [114]

Answer:

The z-score for a data value of 121 is -2.29.

Step-by-step explanation:

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

$\mu = 137, \sigma = 7$