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Vinvika [58]
3 years ago
5

If c = 30 and B = 65 degrees, find b.

Mathematics
1 answer:
elena-s [515]3 years ago
7 0

B is equivalent to Candice.

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Alsion saves $29.26 each month. How many months will it take her to save enough money to buy a stereo for $339.12?
Darya [45]

Answer: 12 months (1 year)

We know that Alision gains $29.26 each month. She wants to buy a stereo for $339.12

You want to divide $339.12 with $29.26 to find the total months.

339.12 / 29.26 = 11.6

CHECK:

You want to round up, since she needs the money to buy a stereo. She's allowed to have more money.

29.26 * 12 = 351.12

It will take Alision 12 months (1 year) to buy her stereo.

5 0
3 years ago
Is this right? Solve the equation. Show your work. 45 = 3b + 69 45- -45 3b 24 3b 24/3 =8 b = 8
Sati [7]
45=3b+69 \\  \\ 3b=-24 \\  \\ b=-8
8 0
2 years ago
A curve is given by y=(x-a)√(x-b) for x≥b, where a and b are constants, cuts the x axis at A where x=b+1. Show that the gradient
ankoles [38]

<u>Answer:</u>

A curve is given by y=(x-a)√(x-b) for x≥b. The gradient of the curve at A is 1.

<u>Solution:</u>

We need to show that the gradient of the curve at A is 1

Here given that ,

y=(x-a) \sqrt{(x-b)}  --- equation 1

Also, according to question at point A (b+1,0)

So curve at point A will, put the value of x and y

0=(b+1-a) \sqrt{(b+1-b)}

0=b+1-c --- equation 2

According to multiple rule of Differentiation,

y^{\prime}=u^{\prime} y+y^{\prime} u

so, we get

{u}^{\prime}=1

v^{\prime}=\frac{1}{2} \sqrt{(x-b)}

y^{\prime}=1 \times \sqrt{(x-b)}+(x-a) \times \frac{1}{2} \sqrt{(x-b)}

By putting value of point A and putting value of eq 2 we get

y^{\prime}=\sqrt{(b+1-b)}+(b+1-a) \times \frac{1}{2} \sqrt{(b+1-b)}

y^{\prime}=\frac{d y}{d x}=1

Hence proved that the gradient of the curve at A is 1.

7 0
2 years ago
Can someone double check that this is correct? If not please correct me :)
bija089 [108]
Yeah you are correct, also I need brainlest please
7 0
2 years ago
A student ate 3/20 of all candies and another 1.2 lb. Another student ate 35 of the candies and the remaining 0.3 lb. Altogether
Ipatiy [6.2K]
The correct question is
<span>A student ate 3/20 of all candies and another 1.2 lb. Another student ate 3/5 of the candies and the remaining 0.3 lb. Altogether, what weight of candies did they eat?</span>

let
x-------> total <span>weight of candies
we know that

x=(3/20)*x+1.2+(3/5)*x+0.3
</span>x=(3/20)*x+(3/5)*x+1.5----> multiply by 20----> 20x=3x+12x+30
20x=15x+30
20x-15x=30
5x=30
x=6 lb

the answer is
6 lb
8 0
3 years ago
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