Answer:
V ≈ 21941.33 yd.
Step-by-step explanation:
I just calculated each side with the help of my trusty calculator! Hope this helped! Comment if you are still confused!
Answer:
the correct answer is B
Step-by-step explanation:
The right answer is c have a nice day
N(17+x)=34x−r
17n+xn=34x-r
xn= 34x - r - 17n
xn-34x= -r - 17n
x(n-34)= -r - 17n
x= (-r - 17n)/(n-34)
In order to solve for this question, let's assign a couple variables.
The variable 't' will represent the number of two-point questions, and the variable 's' will represent the number of six point questions.
From the given, we can already form two equations:
t + s = 36
("An exam... contains 36 questions")
2t + 6s = 148
("An exam worth 148 points... Some questions are worth 2 points, and the others are worth 6 points")
Before we begin calculating anything, we can simplify the second equation we made, since all the numbers are divisible by 2:
2t + 6s = 148
t + 3s = 74
Now let's refer back to the first equation. We can subtract both sides by 's' (you could also subtract both sides by 't', but I personally think that this will make solving the equation less difficult):
t + s = 36
t = 36 - s
This effectively gives us a value for the variable 't'. We can assign this value back into our first equation:
t + 3s = 74
(36 - s) + 3s = 74
36 + 2s = 74
2s = 38
s = 19
Input 's' into our second equation to solve for 't':
t = 36 - s
t = 36 - 19
t = 17
There are 17 two-point questions and 19 six-point questions
- T.B.
