Ask question

Ask question

All categories

Angelina_Jolie [31]

3 years ago

6

How to find the measuremnt of an unknown side of a triangle

1 answer:

antiseptic1488 [7]3 years ago

8 0

Answer:

Can you provide a screenshot or elaborate more on your question please?

Step-by-step explanation:

You might be interested in

Katie knew that 70 + 70 = 140. Explain how she can use this double to solve 70 + 89.

grigory [225]

Just add 19 to 140.

8 0

3 years ago

Read 2 more answers

Evaluate and simplify each square root(simplest form). To create a square root symbol type sqrtt.

Sav [38]

All this is, is plugging in numbers. Then taking the square root of it. The first one would be the square root of 6 squared - 4(5)(-3). That would simplify to the square root of 36+60. Then add the numbers to get the square root of 96. The square root of 96 is about 9.798. I hope that helped. If you still need help with the second one or with the rest of the formula (if there is one) just ask!

5 0

3 years ago

Find the unknown length of y. Please help ASAP!!!!!!!! :(

lara [203]

We assume the slope is a constant, so the rise is proportional to the run.

... y/(4 ft) = (31 ft)/(3 ft)

... y = (4/3)·(31 ft)

... y = 41 1/3 ft = 41 ft 4 in

6 0

3 years ago

Victor spent 1/2 of his salary on rent, 1/4 of the remainder on food and saved \mbox{Sh 1500). How much was his salary?

8090 [49]

Nag basa nito walang jõwa

6 0

1 year ago

The hypotenuse of a right triangle is 5cm long the longer leg is 1cm longer than the shorter leg find the side lengths of the tr

Anvisha [2.4K]

Answer:

<em>Shorter leg=3</em>

<em>Longer leg=4</em>

Step-by-step explanation:

<u>Equations</u>

In a right triangle, Pythagora's Theorem is satisfied. Being a the hypotenuse, b and c the legs of the triangle, then:

$a^2=b^2+c^2$

Let's call

x=the shorter leg of the triangle

The longer leg is 1 cm longer than the shorter leg, thus:

x+1=the longer leg.

Since the hypotenuse is 5 cm long:

$5^2=x^2+(x+1)^2$

Operating:

$25=x^2+x^2+2x+1$

Swapping sides and simplifying:

$2x^2+2x+1=25$

Subtracting 25:

$2x^2+2x-24=0$

Dividing by 2:

$x^2+x-12=0$

Factoring:

$(x-3)(x-4)=0$

We have two possible solutions:

x=3, x=4

The longer leg is x+1.

If x=3, x+1=4

If x=4, x+1=5. This solution is not valid because one leg would be equal to the hypotenuse.

Thus, the solution is:

Shorter leg=3

Longer leg=4

5 0

3 years ago