Answer:
x = number of tickets sold for $26 = 3900 tickets
y = number of tickets sold for $40 = 2100 tickets
Step-by-step explanation:
A 6000-seat theater has tickets for sale at $26 and $40. How many tickets should be sold at each price for a sellout performance to generate a total revenue of $185,400?
Let
x = number of tickets sold for $26
y = number of tickets sold for $40
x + y = 6000
x = 6000 - y
$26 × x + $40 × y= $185, 400
26x + 40y = 185400
Substitute
26(6000 - y) + 40y = 185400
156000 - 26y + 40y = 185400
Collect like terms
- 26y + 40y = 185400 - 156000
14y = 29400
y = 29400/14
y = 2100 tickets
x = 6000 - y
x = 6000 - 2100
x = 3900 tickets
Hence
x = number of tickets sold for $26 = 3900 tickets
y = number of tickets sold for $40 = 2100 tickets
Answer:
x = 13/8
Step-by-step explanation:
sqrt(8x-4) +8 = 11
Subtract 8 from each side
sqrt(8x-4) +8-8 = 11-8
sqrt(8x-4) =3
Square each side
(sqrt(8x-4))^2 =3^2
8x-4 = 9
Add 4 to each side
8x-4+4 = 9+4
8x = 13
Divide by 8
8x/8 = 13/8
x = 13/8
Answer:
There should be a number of 14 students in each row
Step-by-step explanation:
Find the factors of 196 then find the Greatest factor pairs which give you the numbers of 14 and 14. Now you have your answer of 14 rows and 14 columns.
Answer:
y+30
Step-by-step explanation:
the sum of the numbers is 15y
the new sum after increase each number by 30 is 15y+450
the new mean 15y+450/15
= y+30
I need to know the rest of the question in order to help you! :D
