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castortr0y [4]
2 years ago
12

Which relation is a function?

Mathematics
2 answers:
Vinvika [58]2 years ago
8 0
What she or he said^^^^
Gemiola [76]2 years ago
6 0

Answer:

A function is a relation in which each input has only one output. In the relation , y is a function of x, because for each input x (1, 2, 3, or 0), there is only one output y. x is not a function of y, because the input y = 3 has multiple outputs: x = 1 and x = 2.

Step-by-step explanation:

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Write a sentence to answer each question:<br><br> How much warmer is 82 than 40?
Lostsunrise [7]

Answer:

82 is 42 degrees warmer than 40

Step-by-step explanation:

if you subtract 40 from 82, you get 42 meaning that the answer will be 42 degrees more than 40

8 0
2 years ago
For the function y = -2+5 sin<br> (x-2)<br> 12<br> what is the maximum value?
Arisa [49]
The maximum value it going to be 12 which will be 16 in the end that is going to be corrrct
7 0
3 years ago
Ill GIVE BRAINELST AND EXTRA POINTS​
wolverine [178]

Answer:

I believe the answer is (-7.4) Not really great at math either

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
(CO6) From a random sample of 68 businesses, it is found that the mean time that employees spend on personal issues each week is
satela [25.4K]

Answer:

(1) (4.82, 4.98)

(2) Large sample size

(3) Yes, the temperature is within the confidence interval of (37.40, 37.60)

(4) (15.083, 15.117)

Step-by-step explanation:

Confidence Interval (CI) = mean + or - (t×sd)/√n

(1) mean = 4.9, sd = 0.35, n = 68, degree of freedom = n-1 = 68 - 1 = 67

t-value corresponding to 67 degrees of freedom and 95% confidence level is 1.9958

CI = 4.9 + (1.9958×0.35)/√68 = 4.98

CI = 4.9 - (1.9958×0.35)/√68 = 4.82

CI is (4.82, 4.98)

(2) Error margin = (t-value × standard deviation)/√sample size

From the formula above, error margin varies inversely as the square root of the sample size. Since the relationship between the error margin and sample size is inverse, increase in one (sample size) will conversely lead to a decrease in the other (error margin)

(3) mean = 37.5, sd = 0.6, n= 100, degree of freedom = n-1 = 100-1 = 99

t-value corresponding to 99 degrees of freedom and 90% confidence level is 1.6602

CI = 37.5 + (1.6602×0.6)/√100 = 37.5 + 0.10 = 37.60

CI = 37.5 - (1.6602×0.6)/√100 = 37.5 - 0.10 = 37.40

37.53 is within the confidence interval (37.40, 37.60)

(4) mean = 15.10, sd =0.08, n = 104, degree of freedom = n-1 = 104-1 = 103

t-value corresponding to 103 degrees of freedom and 97% confidence interval is 2.2006

CI = 15.10 + (2.2006×0.08)/√104 = 15.10 + 0.017 = 15.117

CI = 15.10 - (2.2006×0.08)/√104 = 15.10 - 0.017 = 15.083

CI is (15.083, 15.117)

4 0
3 years ago
13°38'35" to decimal degrees
babymother [125]

divide 35 by 3600

 divide 38 by 60

add them together

35/3600 = 0.009722

38/60=0.6333

0.6333+0.009722 = 0.64305

 so 13.64305 degrees. round answer as necssary

4 0
3 years ago
Read 2 more answers
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