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castortr0y [4]
3 years ago
12

Which relation is a function?

Mathematics
2 answers:
Vinvika [58]3 years ago
8 0
What she or he said^^^^
Gemiola [76]3 years ago
6 0

Answer:

A function is a relation in which each input has only one output. In the relation , y is a function of x, because for each input x (1, 2, 3, or 0), there is only one output y. x is not a function of y, because the input y = 3 has multiple outputs: x = 1 and x = 2.

Step-by-step explanation:

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In Euclidean geometric terms, which of the below would be the best description of a<br> LINE?
Naddika [18.5K]

Answer:

It is a straight object that begins at a point and extends forever in one direction. It is a straight object that extends infinitely in opposite directions without any width or thickness.

7 0
3 years ago
How do you find the 50th term of the sequence of 5,-2,-9,-16......
Natasha2012 [34]

To find the 50th term in this sequence, first you need to find how what the sequence is. To get from 5 to -2 you're subtracting 7, to get from -2 to -9, you subtract another 7. In order to get the next number you go down by multiples of 7: 5 - 7 = -2; 5 - 14 = -9 and so on). So all you have to do is multiply 7 by 50 to get 350 and subtract that from 5 to get -345.


Hope this helps,

♥<em>A.W.E.</em><u><em>S.W.A.N.</em></u>♥

4 0
3 years ago
DOES ANYONE KNOW THIS PLEASE HELP IM TIMED FOR 5 minutes
Marrrta [24]

Answer:

y= 5x......eqn(1)

-2x+2y= 12......eqn(2)

now

substituting value of eeqn(1) in eqn(2) ,

-2x+2(5x) =12

-2x + 10x = 12

8x = 12

X = 12 ÷ 8

X= 3/2

now put value of X in eqn (1)

y= 5x

y = 5 × 3/2

y = 15/2

Step-by-step explanation:

not sure any ans but I tried my best : )

3 0
3 years ago
Use calculus to find the volume of the following solid S:
Troyanec [42]

S casts a "shadow" on the x-y plane given by the set

S' = \left\{(x,y) ~:~ -1 \le x \le 1 \text{ and } x^2 \le y \le 1\right\}

Each cross section is a square whose side length is determined by the vertical distance between y = 1 and y = x², which is |1 - x²|. But since -1 ≤ x ≤ 1, this distance simplifies to 1 - x².

The volume of an infinitesimally thin section is then (1 - x²)² ∆x (where ∆x represents its thickness), and so the volume of S is

\displaystyle \int_{-1}^1 (1-x^2)^2 \, dx = \int_{-1}^1 (1 - 2x^2 + x^4) \, dx

The integrand is even, so this integral is equal to twice the integral over [0, 1] :

\displaystyle \int_{-1}^1 (1-x^2)^2 \, dx = 2 \int_0^1 (1 - 2x^2 + x^4) \, dx = 2 \left(1 - \frac23 + \frac15\right) = \boxed{\frac{16}{15}}

4 0
2 years ago
Pls show work! questions on pic
Lena [83]

Answer:

a.(10,23)

b.(7,30)

e.(20,20)

Step-by-step explanation:

We are given that

x=Width of garden

y=Length of garden

According to question

x\geq 5

y\geq 20

Perimeter of rectangle=2(x+y)

Where x=Width  of rectangle

y=Length of rectangle

Fencing used =2(x+y)

2(x+y)\leq 80

First we change inequality  into equality

x=5...(1)

y=20...(2)

2(x+y)=80

x+y=40...(3)

Substitute x=0 in equation (3)

y=40

Substitute y=0  in equation (3)

x=40

Substitute x=0 and y=0 in equation (3)

2(x+y)\leq 80

0\leq 80

It is true. Therefore, the  shaded region below the line.

0\geq 5

0\geq 20

These are false equation .Therefore, the shaded region above the line.

Substitute x=5 in equation (3)

5+y=40

y=40-5=35

Substitute y=20 in equation (3)

x+20=40

x=40-20=20

Intersection point of equation (1) and (3) is (5,35) and intersect point of equation (2) and (3) is (20,20).

Now,

a.(10,23)

Substitute in

2(x+y)\leq 80

2(10+23)\leq 80

66\geq 80

10>5 and 23>20

it satisfied all inequality.

Hence, it is a solution.

b.(7,30)

7>5

30>20

2(7+30)=74

it satisfied all inequality.

Hence, it is a solution.

c.(18,25)

18>5

25>20

2(18+25)=86>80

It does not satisfied third inequality

Hence, it is not a solution.

d.(8,35)

8>5

35>20

2(8+35)=86>80

It does not satisfied third inequality

Hence, it is not a solution.

e.(20,20)

2(20+20)=80

20>5

20=20

it satisfied all inequality.

Hence, it is a solution.

4 0
3 years ago
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