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saul85 [17]
3 years ago
10

Find two numbers the quotient between. Then estimate the quotient. 41÷3

Mathematics
1 answer:
AleksandrR [38]3 years ago
5 0

Answer:

The quotient is between 10 and 15, and the exact answer is 13 with the remainder of 2: 13R2.

Step-by-step explanation:

41 ÷ 3 is a very long answer so do 39 ÷ 3 which equals 13 and since you can't divide 2 by three without negatives, just do it as a remainder of 2, or R2, which means the answer is 13 with the remainder of 2, or just 13R2.

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Can someone help me with this question? <br> (2,5) and (10,3) What is the slope and the y-intercept
Paha777 [63]

Answer:

slope is -1/4

y intercept is 11/2

Step-by-step explanation:

the slope is (3-5)/(10-2) = -2/8 = -1/4 (using the slope formula)

the y intercept we can set up an equation, y= mx + b

we already know m, which is -1/4 (the slope), and to find b, we could just plug in one of the points to get

5 = (-1/4)*2+b

solve the equation

b = 11/2

4 0
3 years ago
If Florist B increases the cost per rose to $5.20,for what number of roses is it less expensive to order from Florist A? From Fl
Alenkinab [10]

Answer:

For<em> </em>38 roses at <em>$5.15</em> per rose, Florist A is Less Expensive then Florist B

For<em> </em>34 roses at <em>$5.20</em> per rose, Florist A is Less Expensive then Florist B

Step-by-step explanation:

The Full Question Reads:

<u><em>Derek wants to order some roses online.  Florist A charges $4.75 per blue rose plus $40 delivery charge.  Florist B charges $5.15 per red rose plus $25 delivery charge.  If Florist B increases the cost per rose to $5.20, for what number of roses is it less expensive to order from Florist A?  From Florist B?</em></u>

To begin we need to understand our given information and what we are actually looking for.

<u>Given Information</u>

Florist A:

charges $4.75 per blue rose

charges $40 per delivery

Florist B:

charges $5.15 per red rose

charges $25 per delivery

Note: in this problem we ignore the colour of the rose (red or blue) as it does not affect our solution or contributes to it. Therefore we shall call our first variable representing the number of roses as x.

The next step is to construct a system of equations representing our problem and our given information. Here we are looking at linear relationships so a linear function of the form:

y=ax+b   Eqn(1).

<em>will suffice where</em>

y: represents the total cost from the Florists (i.e. number of roses and delivery charges). Dependent Variable

x: represents the number of roses purchased from the Florists. Independent Variable

a: is our relationship factor between y and x

b: is our constant which in this problem is the <em>delivery charge</em> value for each florist.  

Since we have two Florists, we will construct two equations, one for each florist, by employing Eqn(1).  and our given information as follow:

Florist A:  y=4.75x+40   Eqn(2).

Florist B:  y=5.15x+25   Eqn(3).

By employing both equations above and writing them as an inequality <em>since we are looking for which value of </em>x<em> (i.e. number of roses) will the less expensive Florist be and then solving for </em>x<em> we have: </em>

<em>4.75x+40</em>

<em>4.75x-5.15x       Gathering all similar terms together</em>

<em>-0.4x                       Simplifying</em>

<em>x>\frac{-15}{-0.4}\\                             Solving for x </em>

<em>x>37.5</em>

<em>(note how < changes to > since any multiplication/devision process of negative sign in an Inequality will change the order of < to > and vice versa). </em>

Since a rose has to be sold as a whole and not half we will say that <em>x>38</em> So we can then plug in the value of x in Eqn(2) and Eqn(3) and find the cost of buying more than 38 roses from each:

Eqn(2):  Florist A:  y(x>38)=4.75*38+40=220.5  

Eqn(3):  Florist B:  y(x>38)=5.15*38+25=220.7

Which tells us that Florist A is less expensive than Florist B by $0.20 for a purchase of more than 38 roses.

Next the question tells us that Florist B increases the cost from $5.15 to $5.20 per rose, which in Eqn(3) denotes our a value and thus Eqn(3). now becomes:

Florist B:  y=5.20x+25   Eqn(3).

Applying the same method like before and solving for the value of x<em> we have: </em>

<em>4.75x+40</em>

<em>4.75x-5.20x       Gathering all similar terms together</em>

<em>-0.45x                       Simplifying</em>

<em>x>\frac{-15}{-0.45}\\                           Solving for x </em>

<em>x>33.3</em>

Similarly as a rose has to be sold as a whole and not half we will say that <em>x>34</em> So we can then plug in the value of x in Eqn(2) and Eqn(3) and find the cost of buying more than 34 roses from each:

Eqn(2):  Florist A:  y(x>34)=4.75*34+40=201.5  

Eqn(3):  Florist B:  y(x>34)=5.15*34+25=201.8

Which tells us that Florist A is again less expensive than Florist B by $0.30 for a purchase of more than 34 roses. It was also shown that as the cost of the rose increased by $0.05 the number of roses for purchase decreased.

4 0
3 years ago
A poll was taken this year asking college students if they considered themselves overweight. A similar poll was taken 5 years ag
Katyanochek1 [597]

Answer:

At 5% significance level, it is statistically evident that    there is nodifference in the proportion of college students who consider themselves overweight between the two poll                                  

Step-by-step explanation:

Given that a poll was taken this year asking college students if they considered themselves overweight. A similar poll was taken 5 years ago.

Let five years ago be group I X and as of now be group II Y

H_0: p_x =p_y\\H_a: p_x \neq p_y

(Two tailed test at 5% level of significance)

                Group I            Group II              combined p

n                  270                 300                         570

favor            120                  140                          260

p                   0.4444            0.4667                   0.4561

Std error   for differene = \sqrt{\frac{0.4561(1-0.4561)}{570} } \\=0.0209

p difference = -0.0223    

Z statistic = p diff/std error =       -1.066

p value =0.2864

Since p value >0.05, we accept null hypothesis.

        At 5% significance level, it is statistically evident that    there is nodifference in the proportion of college students who consider themselves overweight between the two poll                                  

7 0
3 years ago
Absolute value to find distance
qaws [65]

Answer:

<h3>              B.</h3>

Step-by-step explanation:

The distance between two any points <em>a</em> i <em>b</em> is |a-b| as we don't know which of them is larger number.

So:

a=-2  and  b=1  means distance |-2-1| = |-3| = 3

{If we know the value of given points we can subtract the smaller one from the larger. It also works: -2<1, so the distance would be 2-(-1)=2+1=3}

6 0
3 years ago
A rational expression had been simplified below.
Lina20 [59]
I agree. All real numbers except -1.
4 0
3 years ago
Read 2 more answers
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