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amid [387]
3 years ago
6

Tina completed two-thirds of her homework George completed 78 of his homework who completed a greater fraction of homework

Mathematics
2 answers:
masya89 [10]3 years ago
3 0
George completed more homework than Tina. Two thirds is equall to 66%
Mice21 [21]3 years ago
3 0
George completed more homework than Tina.
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Please apply the properties of rational exponents to simplify expressions with radical or rational exponents. Explain the steps
schepotkina [342]

Step-by-step explanation:

<u>Product property</u>

  • If the bases are the same, you don't multiple them. However, if they are the same, you do multiple for example : (2³ * 2¹ = 2⁴.when the bases are the same) (2³ * 3¹ =6⁴. When the bases are not the same
  • We add the index.

<u>Quotient</u><u> </u><u>property</u>

  • Same here, if the bases are the same, they stay the way they were
  • We subtract the index

<u>Power</u><u> </u><u>property</u>

  • Here we multiple the index because of the bracket for example : (9²)²= 9⁴

<u>Negetive</u><u> </u><u>exponent</u><u> </u><u>property</u>

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6 0
3 years ago
The ratio of children to teachers at preschool is 14:5. How many children are at the preschool if there are 30 teachers
elena55 [62]

If the ratio is 14 childen to every 5 teachers, and there are thirty teachers... there are 84 children. hope I could help!

6 0
3 years ago
Read 2 more answers
Consider a chemical company that wishes to determine whether a new catalyst, catalyst XA-100, changes the mean hourly yield of i
kolezko [41]

Answer:

Null hypothesis:\mu = 750  

Alternative hypothesis:\mu \neq 750  

t=\frac{811-750}{\frac{19.647}{\sqrt{5}}}=6.943  

p_v =2*P(t_{4}>6.943)=0.00226  

If we compare the p value and a significance level assumed \alpha=0.05 we see that p_v so we can conclude that we reject the null hypothesis, and the actual true mean is significantly different from 750 pounds per hour.  

Step-by-step explanation:

Data given and notation

Data:    801, 814, 784, 836,820

We can calculate the sample mean and sample deviation with the following formulas:

\bar X =\frac{\sum_{i=1}^n X_i}{n}

s=\sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}}

\bar X=811 represent the sample mean  

s=19.647 represent the standard deviation for the sample

n=5 sample size  

\mu_o =750 represent the value that we want to test  

\alpha represent the significance level for the hypothesis test.  

t would represent the statistic (variable of interest)  

p_v represent the p value for the test (variable of interest)  

State the null and alternative hypotheses to be tested  

We need to conduct a hypothesis in order to determine if the mean is different from 750 pounds per hour, the system of hypothesis would be:  

Null hypothesis:\mu = 750  

Alternative hypothesis:\mu \neq 750  

Compute the test statistic  

We don't know the population deviation, so for this case is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:  

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}} (1)  

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".  

We can replace in formula (1) the info given like this:  

t=\frac{811-750}{\frac{19.647}{\sqrt{5}}}=6.943  

Now we need to find the degrees of freedom for the t distirbution given by:

df=n-1=5-1=4

What do you conclude?  

Compute the p-value  

Since is a two tailed test the p value would be:  

p_v =2*P(t_{4}>6.943)=0.00226  

If we compare the p value and a significance level assumed \alpha=0.05 we see that p_v so we can conclude that we reject the null hypothesis, and the actual true mean is significantly different from 750 pounds per hour.  

4 0
3 years ago
Confused on this part
Andre45 [30]

Answer:

The first 2 and the last one

Step-by-step explanation:

You need to have an input per output, and to choose one or multiple the need to have a continuous pattern. Ex.+5 ad -2 on both sides every time would be a linear function.  

6 0
2 years ago
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Mila [183]
77 percent is the correct answer
5 0
3 years ago
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