Hello,
2 cases:
if 1/3*q-5>0 then
|1/3*q-5|=1/3*q-5
1-|1/3*q-5|=-6
1-(1/3*q-5)=-6
1-1/3*q+5=-6
6-1/3*q=-6
-1/3*q=-12
q=36
else
|1/3*q-5|=-(1/3*q-5)
1-|1/3*q-5|=-6
1+(1/3*q-5)=-6
1+1/3*q-5=-6
-4+1/3*q=-6
1/3*q=-2
q=-6
Answer:
open
Step-by-step explanation:
Answer:
Exercise 1:
base [b]=8cm
perpendicular [p]=6cm
hypotenuse [h]=?
<u>By</u><u> </u><u>using</u><u> </u><u>Pythagoras</u><u> </u><u>law</u>
h²=p²+b²
h²=6²+8²
h=√100
h=10cm
<u>So</u><u> </u><u>another</u><u> </u><u>side's</u><u> </u><u>length</u><u> </u><u>is</u><u> </u><u>1</u><u>0</u><u>c</u><u>m</u>
<u>Exercise</u><u> </u><u>2</u><u>:</u>
base [b]=6m
perpendicular [p]=bm
hypotenuse [h]=8m
By using Pythagoras law
h²=p²+b²
8²=b²+6²
b²=8²-6²
b=√28=2√7 0r 5.29 or 5.3
So height of kite is√<u>28</u><u>o</u><u>r</u><u> </u><u>2√7 0r 5.29 or 5.3 m</u>
Step-by-step explanation:
[Note: thanks for translating]
1,000,000, because its the 1st 7 digit number and it happens to be even
multiply 14 x 2.54
14 x 2.54 = 35.56 centimeters
