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Dima020 [189]
3 years ago
14

6(3c−5d+6)=????????????????????????

Mathematics
2 answers:
julsineya [31]3 years ago
7 0

Answer:

18c-30d+36

Step-by-step explanation:

vesna_86 [32]3 years ago
7 0

Answer:

6(3c -5d +6)  (use the distributive property)

18c -30d + 36  (you can't simplify any further, so this should be the answer)

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(Multiplying and Dividing with Scientific Notation LC)
Assoli18 [71]

The product in scientific notation is 8*10^2

<h3>How to multiply and divide in scientific notation?</h3>

Here we want to find the product between 4*10^6 and 2*10^6, and write that in scientific notation.

First, we can solve the direct product:

(4*10^6)*(2*10^6) = (4*2)*(10^6*10^6)

Here we used the fact that we can multiply in any order we want.

Now we will use the property:

a^n*a^n = a^{n + m}

(4*2)*(10^6*10^6) = 8*10^{6 + 6} = 8*10^12

The correct option is the second one, counting from the top.

If you want to learn more about scientific notation:

brainly.com/question/5756316

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7 0
2 years ago
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If the nurse to patient ratio is 3:15, how many nurses would you expect to see in a unit with 37 patients?
Yanka [14]
If there are 3 nurses to every 15 patients, that means there is 1 nurse to every 5 patients since we can divide by 3 to simplify the ratio.
in order to find how many nurses would care for 37 patients, we can divide by 5.
37/5 = 7.4 nurses.
however, we cannot have .4 of a nurse, so you can either say 7 nurses or 8 nurses, but 7.4 rounds down to 7.
4 0
2 years ago
Which of the following expressions is not equal to X^3?
Musya8 [376]

Answer:

D. x. x^7 . x^-4

Step-by-step explanation:

A. X^5 . X^-4 .X^2=X^(5-4+2)= X^3

B. X^-2 .X^9 .x^-4=X^(-2+9-4)= X^3

C.x^0 . x^10 . x^-7=X^(0+10-7)= X^3

D. x. x^7 . x^-4=X^(1+7-4)= X^4

6 0
3 years ago
Someone help please.
Svetradugi [14.3K]

Answer:

9

Step-by-step explanation:

The value of c is given as 63 and it wants this value to be divided by 7

63 ÷ 7 = 9

5 0
3 years ago
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Which expression is equilavent to x+2x+y+2y
Dominik [7]
2x+2+3y yw lolllllll
7 0
3 years ago
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