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Vesnalui [34]
3 years ago
7

5x+2y=21 – 2x+6y=-34

Mathematics
2 answers:
Arisa [49]3 years ago
5 0

Solve for the first variable in one of the equations, then substitute the result into the other equation.

Point Form:(97/17,−64/17)

Equation Form: x=97/17, y=−64/17

plz mark me as brainliest :)

Anvisha [2.4K]3 years ago
4 0

Answer:

Step-by-step explanation:

Question 1

5x+2y=21

5x+2y+−2y=21+−2y

5x=−2y+21

Step 2: Divide both sides by 5

5x/5=-2y+21/5

Answer =-2/5 y+21/5

– 2x+6y=-34

Question 2

−2x+6y=−34

Step 1: Add -6y to both sides.

−2x+6y+−6y=−34+−6y

−2x=−6y−34

Step 2: Divide both sides by -2.

-2x/-2=-6y=-34/2

x=3y+17

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Isolate the variable by dividing each side by factors that don't contain the variable.

a=-  \frac{ x^{2}-  \sqrt{( x^{3} + x^{2} b+12x-72(x-2)-2x} }{x-2} ,-  \frac{ x^{2}+  \sqrt{( x^{3} + x^{2} b+12x-72(x-2)-2x} }{x-2}

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b= \frac{12}{x}+ \frac{72}{ x^{2} }-2+2a- \frac{4a}{x}+ \frac{ a^{2} }{x}- \frac{2a^{z} }{ x^{2} }

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The quadratic mean of two real numbers x and y equals p (x 2 y 2)/2. By computing the arithmetic and quadratic means of differen
BARSIC [14]

Answer:

The quadratic mean of 2 real positive numbers is greater than or equal to the arithmetic mean.

Step-by-step explanation:

x and y      Quadratic Mean       Arithmetic mean

3 and 3                    3                                    3

2 and 3                   2.55                               2.5

3 and  6                  4.74                                4.5

2 and 5                   3.8                                  3.5

2 and 17                 12.1                                   9.5

18 and 28              23.5                                  23

10 and  48             34.7                                  29

The quadratic mean is always greater than the arithmetic mean except when  x and y are the same.

When the difference between the pairs is  small the difference in the means is also small. As that difference increases the difference in the means also increases.

So we conjecture that the quadratic mean is always greater than or equal to the arithmetic mean.

Proof.

Suppose it is true then:

√(x^2 + y^2) / 2) ≥ (x + y)/2       Squaring  both sides:

(x ^2 + y^2) / 2 ≥ (x + y)^2 / 4    Multiply through by 4:

2x^2 +2y^2  ≥  (x + y)^2

2x^2 +2y^2 >=  x^2 + 2xy + y^2

x^2 + y^2 >= 2xy.

x^2 - 2xy + y^2 ≥ 0

(x - y)^2 ≥ 0

This is true  because the square of any real number is positive so the original inequality must also be true.

6 0
3 years ago
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